root.right = convertSortedLinkedListToBST(n - n / 2 - 1); return root; } public static void main(String[] args) { SortedLinkedListToBSTMain list = new SortedLinkedListToBSTMain(); // Creating a linked list Node
到讨论区发现solution-2的解法:计数得到节点总数,知道节点数就可以确定一种满足要求的BST结构,然后使用中序遍历,将列表元素填入BST对应节点。 Description 109. Convert Sorted ListtoBinarySearch Tree Medium238290AddtoList Share Given the headofa singly linked listwhereelements are sortedinascendingorder, convert ...
Description Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example...
node.left=sortedListToBST(head); node.right=sortedListToBST(cur.next); }returnnode; } } Here is the improvement: When we look through the current linked list from the head to the last node, in the end we can find the middle node the node ahead of middle node at the same time. Co...
TreeNode*sortedListToBST(ListNode*head) {//base cases//1.NULL listif(!head)returnNULL;//2. single node listif(!head->next)returnnewTreeNode(head->val);//find the middle of the linked list//using floyd's hair & tortoise algorithmListNode*slow=head; ...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 给出一个所有元素以升序排序的单链表,将它转换成一棵高度平衡的二分查找树. 【题目链接】 www.lintcode.com/en/problem/convert-sorted-list-to-balanced-bst/ ...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 分析 将链表转化为平衡的二叉排序树,可以用上一题的思路,将中间的点作为根节点,左边的为左子树,右边的为右子树。依次递归即可。由于链表统计长度比较麻烦,先转化为数组即可。
LeetCode 109. Convert Sorted List to BST DescriptionGiven a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.For this problem, a height-balanced binary tree is defined as a binary tree in ... 文章...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. ...
426. Convert Binary Search Tree to Sorted Doubly Linked List 方法1: inorder traversal 易错点 Convert a BST to a sorted circular doubly-linked list in-place. Think of the left and right pointers as synonymo... 查看原文 LeetCode 426. Convert Binary Search Tree to Sorted Doubly Linked List-...