既然是由两个有序数组拼接而成,那么只需找到断点,然后进行两次二分查找就行. Time complexity: O(N) view code /** * --- * Copyright (c) 2016 crazyacking.All rights reserved. * --- * Author: crazyacking * Date : 2016-03-01-21.22 */ #include <queue> #include <cstdio> #include <s...
代码 // Search in Rotated Sorted Array II// Time Complexity: O(n),Space Complexity: O(1)publicclassSolution{publicbooleansearch(int[]nums,inttarget){intfirst=0,last=nums.length;while(first!=last){finalintmid=first+(last-first)/2;if(nums[mid]==target)returntrue;if(nums[first]<nums[mid...
publicclassSolution {/*** param A : an integer ratated sorted array and duplicates are allowed * param target : an integer to be search * return : a boolean*/publicbooleansearch(int[] A,inttarget) {if(A ==null|| A.length == 0)returnfalse;intlb = 0, ub = A.length - 1;while(...
https://leetcode.com/problems/search-in-rotated-sorted-array/description/ Given the array nums after the possible rotation and an integer target, return the index of target if it is in nums, or -1 if it is not in nums. You must write an algorithm with O(log n) runtime complexity. ...
Follow up for "Search in Rotated Sorted Array": What if duplicates Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. class Solution { public: //1,1, 1,2,1,1,1,恰好左中右都是1,这时我们 ++左下标,--右下标 ...
Time Complexity: The time complexity of the brute force approach is (𝑛), where 𝑛n is the number of elements in the array. This is because in the worst case, we might have to check every element in the array. Best Case: The target is the first element, so the time complexity ...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. ...
Find Minimum in Rotated Sorted Array II Follow up for "Find Minimum in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose a sorted array is rotated at some pivot ......
Search in Rotated Sorted Array II Follow up for "Search in Rotated Sorted Array": What ifduplicatesare>[1,3,1,1,1], 3 Would this affect the run-time complexity? How and why? --run-time的最坏情况是O(n)了,因为特殊情况出现的时候需要额外处理,可能做线性搜索 ...
You are given a target value to search. If found in the array return its index, otherwise return-1. You may assume no duplicate exists in the array. Your algorithm's runtime complexity must be in the order ofO(logn). Example 1: ...