这是我在逛 Stack Overflow 时遇见的一个高分问题:Why is processing a sorted array faster than an unsorted array?,我觉得这是一个非常好的用来讲分支预测(Branch Prediction)的例子,分享给大家看看 一、问题引入 先看这个代码: #include <algorithm> #include <ctime> #include <iostream> #include <stdint....
In case of>comparison, in sorted array the branching behavior is very consistent: first, theifcondition is consistently false, then it is consistently true. This aligns very well with even the simplest branch prediction. In unsorted array the result of>condition is essentially random, thus thwarti...
You are the operator of a junction and you hear a train coming. You have no idea which way it will go. You stop the train to ask the captain which direction he wants. And then you set the switch appropriately. Trains are heavy and have a lot of inertia. So they take forever to st...
Processing a sorted array can be faster than processing an unsorted array because certain algorithms and operations have a lower average time complexity when the input is already sorted. For example, the time complexity of the binary search algorithm is O(log n) for a sorted array...
(a,b)=>a-b)array=SortedArray.parse([4,2,3,4],(a,b)=>a-b)// throws UnsortedArrayError// "SortedArray.unsafe" does not verify the array is actually sorted.// Use when performance is critical and one can assume the array is sorted.array=SortedArray.unsafe([4,2,3,4],(a,b)=...
Does a sorted array run faster than an unsorted array in Java?Brian L. Gorman
We all know that even though the array is rotated in some pivot, that it still contains sorted information for we can use instead of threat them like unsorted array. so Binary Seach will be used in all those solutions. and you have to keep in mind, that each time, if we split the ...
2. Sorted versus unsorted TheSortedinterfaces extend the non-sorted interfaces with queries that only a sorted collection can perform efficiently, such asminKey()andnextHigherKey(k). At minimum, sorted interfaces add methodsminKey,maxKey,nextHigherKey,nextLowerKey, andforRange, plus iterators that retu...
The values original position within its unsorted array. getValue public String getValue() Gets the value that will be sorted. Returns: The value that will be sorted. setIndex public void setIndex(int withIndex) Sets the values original position within its unsorted array. ...
这是我在逛 Stack Overflow 时遇见的一个高分问题:Why is processing a sorted array faster than an unsorted array?,我觉得这是一个非常好的用来讲分支预测(Branch Prediction)的例子,分享给大家看看 一、问题引入 先看这个代码: 注意:这里特地没有加随机数种子是为了确保 data 数组中的伪随机数始终不变,为....