java代码: 1/**2* Definition for singly-linked list.3* class ListNode {4* int val;5* ListNode next;6* ListNode(int x) {7* val = x;8* next = null;9* }10* }11*/12publicclassSolution {13publicListNode sortList(ListNode head) {14if(head==null||head.next==null)returnhead;15ListN...
Title: Sort a linked list inO(nlogn) time using constant space complexity. 思路:考虑快速排序和归并排序,但是我的快速排序超时了 ListNode* sortList(ListNode*head) {if(!head)returnNULL;intm_val = head->val; ListNode* left = NULL,*right =NULL; ListNode* p_left = NULL,*p_right =NULL; Lis...
循环版本号主函数例如以下: ListNode*sortList(ListNode*head){ListNode*cur=head;intsize=0;while(cur){size++;cur=cur->next;}ListNode*pre;for(intw=1;w<=size;w*=2){cur=head;for(inti=0;i<size;i+=w*2){ListNode*h1=cur,*h2=getNode(cur,w),*next=getNode(cur,2*w);cur=merge(h1,min(...
注意:要考虑空链表,单个元素的链表,以及多个元素的链表。 LeetCode的代码: 1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 class Solution { 10 public: 11 ListNod...
Sort a linked list in O(n log n) time using constant space complexity. Example 1: Input: 4->2->1->3 Output: 1->2->3->4 Example 2: Input: -1->5->3->4->0 Output: -1->0->3->4->5 解题思路:回想排序算法,线性对数时间复杂度的有:快速排序,堆排序,归并排序,前两种暂时没实现...
首先用快慢指针的方法找到链表中间节点,然后递归的对两个子链表排序,把两个排好序的子链表合并成一条有序的链表。归并排序应该算是链表排序最佳的选择了,保证了最好和最坏时间复杂度都是nlogn,而且它在数组排序中广受诟病的空间复杂度在链表排序中也从O(n)降到了O(1) ...
My code: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{publicListNodesortList(ListNodehead){if(head==null)returnnull;intcount=0;ListNodetemp=head;while(temp!=null){count++;...
classSolution:defsortPeople(self,names:List[str],heights:List[int])->List[str]:combined=sorted(zip(heights,names),reverse=True)#基于升高逆序排序return[namefor_,nameincombined] 复杂度分析: 时间复杂度:O(NlogN),其中N是列表的长度。这是因为sorted函数基于比较的排序算法(如Timsort),其时间复杂度通常...
key parameter to specify a function to be called on each list element prior to making comparisons. The value of the key parameter should be a function that takes a single argument and returns a key to use for sorting purposes. 通俗讲,key 用来决定在排序算法中 cmp 比较的内容,key 可以是任何...
LeetCode – Sort List: Sort a linked list in O(n log n) time using constant space complexity. Analysis If this problem does not have the constant space limitation, we can easily sort using a sorting method from Java SDK. With the constant space limitation, we need to do some pointer ma...