SortMap pd = new SortMap(); List<String> cixu = pd.sortMapByValue((HashMap<String,Integer>)first); Iterator<String> ite = cixu.iterator(); while(ite.hasNext()) { System.out.println(ite.next()); } } } 分享
Mapis a common data type when we need to manage key-value associations. TheLinkedHashMapis a popular choice, primarily known for preserving the insertion order. However, in many real-world scenarios, we often need to sort the elements of aLinkedHashMapbased on their values rather than keys....
In this tutorial, we’ll learn how to sort aLinkedHashMapbased on its values. We’ll look at several approaches how to achieve it. 2. Sort With Conversion toList The simplest way to sort aLinkedHashMapby values is to convert it into a list of key-value pairs. After that, we sort ...
自定义类知道自己应该如何排序,也就是按值排序,具体为自己实现Comparable接口或构造一个Comparator对象,然后不用Map结构而采用有序集合(SortedSet, TreeSet是SortedSet的一种实现),这样就实现了Map中sort by value要达到的目的。就是说,不用Map,而是把Map.Entry当作一个对象,这样问题变为实现一个该对象的有序集合或...
实际项目或者业务当中,经常会有需求要求对 hashmap 按值排序,并返回指定顺序的 TopN 个元素,今天就来分享下具体的代码及其原理实现。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 package com.bj.test.top10; import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; impor...
publicMap<String, String>sortMapByValue(Map<String, String> oriMap){ Map<String, String> sortedMap =newLinkedHashMap<String, String>();if(oriMap !=null&& !oriMap.isEmpty()) { List<Map.Entry<String, String>> entryList =newArrayList<Map.Entry<String, String>>(oriMap.entrySet()); ...
// 按照Map的键进行排序 Map<String, Integer> sortedMap = codes.entrySet().stream() .sorted(Map.Entry.comparingByKey()) .collect( Collectors.toMap( Map.Entry::getKey, Map.Entry::getValue, (oldVal, newVal) -> oldVal, LinkedHashMap::new ...
Map<String,Integer>unsortedMap=Map.of("a",1,"c",3,"b",2,"e",5,"d",4);LinkedHashMap<String,Integer>sortedMap=unsortedMap.entrySet().stream().sorted(Map.Entry.comparingByValue()).collect(Collectors.toMap(Map.Entry::getKey,Map.Entry::getValue,(oldValue,newValue)->oldValue,LinkedHash...
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MapSortByValueimport java.util.*; public class TestLhh { public static void main(String[] args){ Map<Long,Double> orimap = new HashMap<>(); orimap.put(1L,3.0); orimap.put(2L,1.0); orimap.put(3L,5.0); orimap = sortMapByValue(orimap); for (Long str : orimap.keySet()){ ...