* If center part is too large (comprises > 4/7 of the array), * swap internal pivot values to ends. */if (less < e1 && e5 < great) {/* * Skip elements, which are equal to pivot values. */while (a[less] == pivot1) { ++less; } while (a[great] == pivot2) {--great;...
String[] strArray = new String[]{"hello","Hello", "Hello kity", "hello kity","D","w","A","z"}; Arrays.sort(strArray ,String.CASE_INSENSITIVE_ORDER); System.out.println(Arrays.toString(strArray)); 1. 2. 3. 运行结果如下: [A, D, hello, Hello, Hello kity, hello kity, w,...
* Sort five evenly spaced elements around (and including) the * center element in the range. These elements will be used for * pivot selection as described below. The choice for spacing * these elements was empirically determined to work well on * a wide variety of inputs. */ int e3 =...
Sorting is arranging elements in an ordered sequence. Over the years, several algorithms were developed to perform sorting on data; for instance merge sort, quick sort, selection sort, or bubble sort. (Another meaning of sorting is categorizing: grouping elements with similar properties.) The oppo...
/* * If center part is too large (comprises > 4/7 of the array), * swap internal pivot values to ends. */ if (less < e1 && e5 < great) { /* * Skip elements, which are equal to pivot values. */ while (a[less] == pivot1) { ++less; } while (a[great] == pivot2) ...
* second terciles of the array. Note that pivot1 <= pivot2. */ int pivot1 = a[e2]; int pivot2 = a[e4]; /* * The first and the last elements to be sorted are moved to the * locations formerly occupied by the pivots. When partitioning ...
* that if there are elements equal to pivot, left points to the * first slot after them -- that's why this sort is stable. * Slide elements over to make room for pivot.*/intn = start - left;//The number of elements to move//Switch is just an optimization for arraycopy in defau...
// Recursively sort non-partition-elements if ((s = b-a) > 1) sort1(x, off, s); if ((s = d-c) > 1) sort1(x, n-s, s); } /*归并排序*/ private static void mergeSort(Object[] src, Object[] dest, int low, int high, ...
(a,lo,hi,lo+initRunLen);return;}/*** March over the array once, left to right, finding natural runs,* extending short natural runs to minRun elements, and merging runs* to maintain stack invariant.*/ComparableTimSortts=newComparableTimSort(a,work,workBase,workLen);intminRun=minRunLength...
printf("Enter elements in array : "); for(i=0;i<n;i++) { scanf("%d",&a[i]); } for(i=0;i<n-1;i++) { for(j=0;j<n-i-1;j++) { if(a[j]>a[j+1]) { temp=a[j]; a[j]=a[j+1]; a[j+1]=temp; }