我们可以通过传递一个可迭代对象给sorted()函数来对字典的值进行排序。 下面是一个简单的示例,演示了如何对字典的值进行排序: AI检测代码解析 # 创建一个字典scores={'Alice':85,'Bob':92,'Charlie':78,'David':95}# 对字典的值进行排序sorted_scores=sorted(scores.values())print(sorted_scores) 1. 2. ...
Sort a dictionary by values¶To sort the dictionary by values, you can use the built-in sorted() function that is applied to dict.items(). Then you need to convert it back either with dictionary comprehension or simply with the dict() function:...
sortedDictValues1(adict): keys = adict.keys() keys.sort() return [adict[key] for in 1. 2. 3. 4. 5. 6. 7. 8. 方法3:通过映射的方法去更有效的执行最后一步 def sortedDictValues1(adict): keys = adict.keys() keys.sort() return map (adict.get,keys ) 1. 2. 3. 4. 5. ...
items.sort()return[valueforkey, valueinitems] defsortedDictValues2(adict): keys = adict.keys() keys.sort()return[dict[key]forkeyinkeys] defsortedDictValues3(adict): keys = adict.keys() keys.sort()returnmap(adict.get, keys) #一行语句搞定:[(k,di[k])forkinsorted(di.keys())] 按...
Then you could just write: print(*sorted(yourdict.values())) 3rd Dec 2018, 2:00 PM HonFu M + 1 Was it really a dictionary? And not a list? 3rd Dec 2018, 2:03 PM HonFu M + 1 If the talk was really about sorting a Python dictionary I find it quite silly tbh. ...
return [value for key, value in items] 又一个按照key值排序,貌似比上一个速度要快点 def sortedDictValues2(adict): keys = adict.keys() keys.sort() return [dict[key] for key in keys] 还是按key值排序,据说更快。。。而且当key为tuple的时候照样适用 ...
If you’d like to sort a dictionary by its keys, you can use the built-insortedfunction along with thedictconstructor: >>>sorted_dictionary=dict(sorted(old_dictionary.items())) If you’d like to sort a dictionary by its values, you can pass a customkeyfunction (one which returns the ...
在Python中,字典的排序是基于键(key)的排序。sort函数可以通过指定键来对字典进行排序。sort函数是Python内置的函数,可以用于对可迭代对象进行排序。它的基本语法如下所示: sorted(iterable, key=key, reverse=reverse) 其中,iterable是要排序的可迭代对象,key是一个用于指定排序的函数,reverse是一个布尔值,用于指定是...
1: 按照键值(value)排序 a = {'a': 'China', 'c': 'USA', 'b': 'Russia', 'd': 'Canada'} b = sorted(a.items(), key=lambda x: x[1], reverse=True) 结果: [('c', 'USA'), ('b', 'Russia'), ('a', 'China'), ('d', 'Canada')] ...
Python sort list of dates In the next example, we sort a list of dates. sort_date.py #!/usr/bin/python from datetime import datetime values = ['8-Nov-19', '21-Jun-16', '1-Nov-18', '7-Apr-19'] values.sort(key=lambda d: datetime.strptime(d, "%d-%b-%y")) ...