一、题目大意 https://leetcode.cn/problems/sort-characters-by-frequency 给定一个字符串 s ,根据字符出现的 频率 对其进行 降序排序 。一个字符出现的 频率 是它出现在字符串中的次数。 返回 已排序的字符串 。如果有多个答案,返回其中任何一个。 示例1: 输入: s = "tree" 输出: "eert" 解释: 'e'出...
题目地址:https://leetcode.com/problems/sort-characters-by-frequency/description/题目描述Given a string, sort it in decreasing order based on the frequency of characters.Example 1:Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' ...
func frequencySort(s string) string { // chToCnt[ch] 表示 s 中 ch 的出现次数 chToCnt := make(map[rune]int) for _, ch := range s { chToCnt[ch] += 1 } // 对 s 中的字符按照出现次数降序排序, // 出现次数相同时,按字符升序排序(以保证相同字符在一起) chs := ([]rune)(s)...
Given a strings, sort it indecreasing orderbased on thefrequencyof the characters. Thefrequencyof a character is the number of times it appears in the string. Returnthe sorted string. If there are multiple answers, returnany of them. Example 1: Input:s = "tree"Output:"eert"Explanation:'e...
LeetCode-Sort Characters By Frequency Description: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once....
[LeetCode] 451. Sort Characters By Frequency Problem Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input:"tree"Output:"eert" Explanation: 'e' appears twice while 'r' and 't' both appear once....
Given a string, sort it in decreasing(降序) order based on the frequency(频率) of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a ...
451. Sort Characters By Frequency 题目 Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input:"tree" Output: “eert” Explanation: ‘e’ appears twice while ‘r’ and ‘t’ both appear once....
// import "strconv"// import "fmt"funcfrequencySort(sstring)string{count:=map[byte]int{}fori:=0;i<len(s);i++{count[s[i]]++}ans:=make([]byte,0,len(s))forlen(count)>0{varkbytevarvintvarchbytemaxcount:=0fork,v=rangecount{ifv>maxcount{maxcount=v ...
0451-Sort-Characters-By-Frequency/cpp-0451 CMakeLists.txt main.cpp 0454-4Sum-II 0455-Assign-Cookies 0470-Implement-Rand10-Using-Rand7 0473-Matchsticks-to-Square 0474-Ones-and-Zeroes 0478-Generate-Random-Point-in-a-Circle 0485-Max-Consecutive-Ones 0490-The-Maze 0494-Target-Sum 0497-Random-Poin...