importjava.util.Arrays;importjava.util.Collections;publicclassDescendingArraySort{publicstaticvoidmain(String[]args){Integer[]array={1,5,3,4,2};// 倒序排序Arrays.sort(array,Collections.reverseOrder());System.out.println("倒序排序后的数组: "+Arrays.toString(array));}} 1. 2. 3. 4. 5. 6....
// Checkifthe array is nearly sortedfor(int k = left; k < right; run[count] = k) {if(a[k] < a[k + 1]) { // ascendingwhile(++k <= right && a[k - 1] <= a[k]); }elseif(a[k] > a[k + 1]) { // descendingwhile(++k <= right && a[k - 1] >= a[k]);fo...
1 // Check if the array is nearly sorted 2 for (int k = left; k < right; run[count] = k) { if (a[k] < a[k + 1]) { // ascending 3 while (++k <= right && a[k - 1] <= a[k]); 4 } else if (a[k] > a[k + 1]) { // descending 5 while (++k <= right...
java Integer[] integerArray = Arrays.stream(array).boxed().toArray(Integer[]::new); Arrays.sort(integerArray, descendingOrder); // 如果需要,可以将排序后的Integer[]数组转换回int[]数组 int[] sortedArray = Arrays.stream(integerArray).mapToInt(Integer::intValue).toArray(); 综上所述,最简...
// Check if the array is nearly sortedfor(intk = left; k < right; run[count] = k) {if(a[k] < a[k +1]) {// ascendingwhile(++k <= right && a[k -1] <= a[k]); }elseif(a[k] > a[k +1]) {// descendingwhile(++k <= right && a[k -1] >= a[k]);for(intlo...
Learn to sort Java ArrayList in ascending and descending order using ArrayList.sort(), Collections.sort(), Comparator interface and Java 8 Streams.
In this post, you will learn how to sort ArrayList in descending order in Java. We will explore the following ways: Using the sort() method Using the Collections.sort() and Collections.reverse() methods Sort ArrayList in descending order in Java using the Collections.sort() method We can ...
// Check if the array is nearly sorted for (int k = left; k < right; run[count] = k) { if (a[k] < a[k + 1]) { // ascending while (++k <= right && a[k - 1] <= a[k]); } else if (a[k] > a[k + 1]) { // descending ...
* (ascending or descending sequence). */ int[] run =new int[MAX_RUN_COUNT +1]; intcount =0; run[0] = left; // Check if the array is nearly sorted for(intk = left; k < right; run[count] = k) { if(a[k] < a[k +1]) {// ascending ...
(ascending or descending sequence).23*/24int[] run =newint[MAX_RUN_COUNT + 1];25intcount = 0; run[0] =left;2627//Check if the array is nearly sorted28for(intk = left; k < right; run[count] =k) {29if(a[k] < a[k + 1]) {//ascending30while(++k <= right && a[k -...