publicint[] sortArrayByParity2(int[] A) {intn=A.length, index =0;int[] result =newint[n];for(inti=0; i<n; i++) {if(A[i]%2==0) { result[index++] = A[i]; } }for(intj=0; j<n; j++) {if(A[j]%2!=0) { result[index++] = A[j]; } }returnresult; } 04 第...
} public void swap(int [] Array,int i,int j){ int temp=Array[i]; Array[i]=Array[j]; Array[j]=temp; }
Sort Array By Parity II Leetcode学习笔记:#922. Sort Array By Parity II Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd,......
922. Sort Array By Parity II # 题目 # Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may
LeetCode-922. Sort Array By Parity II i++文章分类运维 Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; ...
Description: Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] ...
:pencil2: 算法相关知识储备 LeetCode with Python :books:. Contribute to HuberTRoy/leetCode development by creating an account on GitHub.
:pencil2: 算法相关知识储备 LeetCode with Python :books:. Contribute to lukelucode/leetCode development by creating an account on GitHub.
/** * 922. Sort Array By Parity II *https://leetcode.com/problems/sort-array-by-parity-ii/description/ * * Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is ...
func sortArray(nums []int) []int { quickSort(nums, 0, len(nums)-1) return nums } func quickSort(nums []int, start int, end int) { if start >= end { return } p := partition(nums, start, end) quickSort(nums, start, p-1) quickSort(nums, p+1, end) } func partition(nums...