代码1: fromcollectionsimportOrderedDictdeffrequency_sort(items):return[i[0]foriinsorted(OrderedDict({i:items.count(i)foriinitems}).items(),key=lambdax:x[1],reverse=True)forninrange(i[1])] 代码2: deffrequency_sort(items):fromcollectionsimportCounterreturn[iforx,cinCounter(items).most_common(...
funcfrequencySort(nums[]int)[]int{// numToCnt[ch] 表示 nums 中数字的出现次数numToCnt:=make(map[int]int)for_,num:=rangenums{numToCnt[num]+=1}// 对 nums 中的数字按照出现次数升序排序,// 出现次数相同时,按数字降序排序。sort.Slice(nums,func(i,jint)bool{ifnumToCnt[nums[i]]!=numToC...
Given an array of integersnums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order. Return thesorted array. Example 1: Input: nums = [1,1,2,2,2,3] Output: [3,1,1,2,2,2] Explanation:...
1636. Sort Array by Increasing Frequency 解题方法 先用collections.Counter计算频数存入字典,然后用sorted方法对字典中的键根据值顺序排序,第二关键字设置为键的倒序,返回一个元组组成的列表temp,其中每个元组的第一位是成员值,第二位是成员出现的次数,从头至尾遍历temp写元素即可。 时间复杂度:O(nlogn) 空间复杂...
func frequencySort(s string) string { // chToCnt[ch] 表示 s 中 ch 的出现次数 chToCnt := make(map[rune]int) for _, ch := range s { chToCnt[ch] += 1 } // 对 s 中的字符按照出现次数降序排序, // 出现次数相同时,按字符升序排序(以保证相同字符在一起) chs := ([]rune)(s)...
0448. Find All Numbers Disappeared in an Array 0451. Sort Characters by Frequency 0453. Minimum Moves to Equal Array Elements 0454.4 Sum I I 0455. Assign Cookies 0456.132 Pattern 0457. Circular Array Loop 0458. Poor Pigs 0460. L F U Cache 0461. Hamming Distance 0462. Minimum Moves to Eq...
【Leetcode】451. Sort Characters By Frequency https://leetcode.com/problems/sort-characters-by-frequency/#/description 特殊的排序,对频率排序。 1.常规思路,先遍历一遍,把频数存入map,再把map的entry存入priorityqueue,最后逐一出队即可。代码:...
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input:"tree" Output: “eert” Explanation: ‘e’ appears twice while ‘r’ and ‘t’ both appear once. So ‘e’ must appear before both ‘r’ and ‘t’. Therefore “eetr” is also a vali...
用map记录下次数,然后不停的遍历map,每次取频次最高的字符放进ans里,最多52个字符 // import "strconv"// import "fmt"funcfrequencySort(sstring)string{count:=map[byte]int{}fori:=0;i<len(s);i++{count[s[i]]++}ans:=make([]byte,0,len(s))forlen(count)>0{varkbytevarvintvarchbytemaxco...
LeetCode451 Sort Characters By Frequency 题目: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: &...Leetcode451. Sort Characters By Frequency 给定一个字符串,请将字符串里的字符按照出现的频率降序排列。 示例 1: 输入: “tree” 输出: “...