Calling reverse() on the array reverses the order to 5, 4, 3, 2, 1. The sort() method puts the items in ascending order. The sort() method calls the String() casting function on every item and then compares the strings to determine the correct order. This occurs even if all items ...
// Find end of run, and reverse range if descending if (c.compare(a[runHi++], a[lo]) < 0) { // Descending while (runHi < hi && c.compare(a[runHi], a[runHi - 1]) < 0) runHi++; reverseRange(a, lo, runHi); } else { // Ascending while (runHi < hi && c.compar...
return; // Arrays of size 0 and 1 are always sorted //如果数组长度小于MIN_MERGE(32)则使用二分排序 // If array is small, do a "mini-TimSort" with no merges if (nRemaining < MIN_MERGE) { int initRunLen = countRunAndMakeAscending(a, lo, hi, c); binarySort(a, lo, hi, lo +...
https://www.geeksforgeeks.org/arrays-sort-in-java-with-examples/Array class is a class containing static methods that are used with arrays in order to search, sort, compare, insert elements, or return a string representation of an array. So let us specify the functions first and later ...
Reversing an Array Thereverse()method reverses the elements in an array: Example constfruits = ["Banana","Orange","Apple","Mango"]; fruits.reverse(); Try it Yourself » By combiningsort()andreverse(), you can sort an array in descending order: ...
superT>c) {assertlo <hi;intrunHi = lo + 1;if(runHi ==hi)return1;//Find end of run, and reverse range if descending//下面的if...else就是寻找自增序列的,if中判断的情况是寻找自然降序的if(c.compare(a[runHi++], a[lo]) < 0) {//Descendingwhile(runHi < hi && c.compare(a[...
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Output: [10, 8, 6, 5, 4, 2] That’s all about sorting a list in reverse order in Java. Also See: Sort an array of strings in Java Sort an array in descending order in Java Sort List in ascending order in Java Rate this post Average rating 4.72/5. Vote count: 32 Thanks...
vals.sort(Comparator.reverseOrder()); System.out.println(vals); } The integers are sorted in ascending and descending orders. The data is sorted in-place; i.e. the original list is modified. $ java Main.java [-4, -2, -1, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8] ...
countRunAndMakeAscending函数: privatestaticintcountRunAndMakeAscending(Object[]a,intlo,inthi){assertlo<hi;intrunHi=lo+1;if(runHi==hi)return1;// Find end of run, and reverse range if descendingif(((Comparable)a[runHi++]).compareTo(a[lo])<0){// Descendingwhile(runHi<hi&&((Comparable...