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(5-x)(2)-(1)This equation simplifies to0=x-1-5+xso 0=x+x-6We now solve this quadratic equation by factorisation.0=(x+3)(x-2)so x+3=0 or x-2=0thereforex=-3 or x=2These values of.x are now substituted into one of the original equations to find thecorresponding values ...
Solve the simultaneous equations y=3x^2-4 (1)y=2x+3(2) 相关知识点: 试题来源: 解析 Sutract equation (2) from equation(1). y=3x2-4 (1) y=2x+3 121 0=(3x2-4)-(2x+3)(2)-(1) This equation simpoifes to 0=3x^2-2x-7 which dass not factorise, so we need to use the ...
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Learn how to solve the simultaneous equations using the substitution and elimination method. Visit BYJU'S to get the solved problems on simultaneous linear equations with a step by step procedure.
(8-2x)=21Forms tw4x+24-2x(error)=212x=-3x =-1.5 and y=11(or 9)o correct equations that would allow eliminatio4x+3y=21n of either x or y eg4x+2y=16or Attemp4x+3y=216x+3y=24ts to solve by substitution and forms a correctequation in either r or y eg4x+3(8-2x)=218-2x-...
(a) shows the graphs whose equations are given in Example 2. Notice that the solutions of these simultaneous equations appear as and , the points of intersection of the two graphs.Similarly, Fig. (b) illustrates the solutions of the simultaneous equations in Example 3.Fig. (b) ...
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