Solve EquationsSolve :1/p + 1/q = 1/f for qSolve for y in terms of x:3x - 5y = 8 相关知识点: 试题来源: 解析 1/p + 1/q = 1/f for q1/q=1/f-1/p=(p-f)/fpq=fp/(p-f)3x - 5y = 8 3x=5y+8x=(5y+8)/3反馈 收藏 ...
In Exercises 3 and 4, solve for y in terms of x.$$ \frac { y ^ { 2 } } { 1 6 } - \frac { x ^ { 2 } } { 9 } = 1 $$ 相关知识点: 试题来源: 解析 $$ y= \pm \frac{4}{3}\sqrt{x^{2}+9} $$ 反馈 收藏 ...
Sign inThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerQuestion: Solve for y in terms of x.lny+2lnx=4+ln10The solution for y in terms of x ...
Solving for y in terms of t, in mathematics, simply translates to rewriting the given equation such that we only have y on one side, while the rest of the equation is on the other side. For this problem, we need to use exponentials because we have to remove the natural logarit...
Solve for {eq}x {/eq} and {eq}y {/eq} in terms of the other variables in the two equations given below. {eq}\displaystyle A x + B y = H\\ C x + D y = G {/eq} The Subject of The Formula In mathematics, we understand tha...
结果一 题目 Solve the differential equation, giving y in terms of x, where x and y=1 at x=1. 答案 y=-1/(3x^2)+(4x)/3 3r2相关推荐 1Solve the differential equation, giving y in terms of x, where x and y=1 at x=1.
for X and Y in terms of x and y, [Hint: To begin, multiply the first equation by cos φ and the second by sinφ, and then add the two equations to solve for X.] 相关知识点: 试题来源: 解析 X=xcos φ +ysin φ; Y=-xsin φ +ycos φ ...
例句与“ solve for x " 变形 干 匹配词 所有 精确 任何 And then we can go back and substitute into either of these equations and solve for x. QED So what we do is, we essentially just solve for x in terms of y. QED We're asked to solve for x and we have this compound...
y=loge(6) Solve for y y=ln(6)≈1.791759469 Assign y y := ln(6) Graph Share Copy Copied to clipboard Examples
Solve for d in terms of A. A=3.142(d2)2Solving for a Value:In order to solve for a value of a variable, the terms separated by the addition or subtraction operation has to be transposed to the other side of the equation and the sign changes. If there are coefficients then...