r=2cos(θ) Solve for r r=2cos(θ) Solve for θ θ=−arccos(2r)+2πn1,n1∈Z θ=arccos(2r)+2πn2,n2∈Z,∣r∣≤2 Graph Share Copy Copied to clipboard
a) solve for {eq}\theta {/eq} as a function of {eq}x.{/eq} b) replace in {eq}f(\theta) {/eq} with you result in part (a) and (c) simplify. {eq}x = 3 \tan(\theta), f(\theta) = \sin(\theta) ...
Solve for {eq}\angle C {/eq} as shown in the figure below. Inscribed Angle Theorem: The inscribed angle theorem tells us that the measure of an inscribed angle is half that of the measure of the arc which it intercepts. An inscribed angle is an angle which has its vertex on the peri...
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from ( 2π ) to find the solution in the third quadrant. (θ =2π -π ) Subtract ( π ) from ( 2π ). (θ =π ) Find the period. ( 2π ) ...
cos(2θ)−10cos(θ)2=−3 Solve for θ θ=πn1+3π,n1∈Z θ=πn1+32π,n1∈Z Graph Examples
Tap for more steps... Step 4.2.2.1 The exact value of is . Step 4.2.3 The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from to find the solution in the fourth quadrant. Step 4.2.4 Simplify . Tap for more ste...
Solvesin2θtanθ+cos2θcotθ−sin2θ=1+tanθ+cotθ View Solution Solve:cotθ2−cotθ=cosecθ2 View Solution View Solution The value ofcotθ−tanθ−2tan2θ−4tan4θ−8cot8θ,is View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT...
for i = 1:361 syms theta2 theta4 eqn1 = a*cos(theta1(1,i)) + b*cos(theta2) - c - d*cos(theta4) == 0; eqn2 = a*sin(theta1(1,i)) + b*sin(theta2) - c - d*sin(theta4) == 0; sol = solve([eqn1,eqn2],[theta2,theta4]); ...
Step 2: Use the identity for sin3αWe can express sin3α using the triple angle formula:sin3α=3sinα−4sin3αSubstituting this into the equation gives:3sinα−4sin3α=4sinα(sin2θ−sin2α) Step 3: Factor out sinαAssuming sinα≠0 (since α≠nπ), we can divide both si...
Tap for more steps... The exact value ofarctan(1)is45. θ=45 θ=45θ=45 Thetangentfunctionis positive in the first and thirdquadrants. To find thesecondsolution, subtract thereference anglefrom180180to find thesolutionin the fourthquadrant. ...