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Then, multiplying on the left both members of the above matrix equation by displaystyleA⁻¹, one gets the solution of the system of linear equations as displaystyleX=A⁻¹B. Methods of solving systems of linear equations range from the introductory, like substitution and elimination, to ...
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To solve for x infractionswe have to eliminate the denominator by cross multiplication and then solve for x. For example, x/4 + 1/2 = 5/2 ⇒ (2x+4)/8 = 5/2 By doing cross multiplication we get, 2(2x + 4) = 8(5)