To numerically solve a differential equation with higher-order (such as 2nd derivative) terms, it can be broken into multiple first-order differential equations by declaring a new variablezzand equationz=y'z=y′. The modified problem is then: ...
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Runge-Kutta 4th order to solve 2nd order ODE Feb 28, 2018 at 1:50pm jamesbellcpp (3) I tried to write a code to solve a 2nd order ODE but somehow it did not work as I intended. the equation is 2y" + 5y' +3y = 0 ,y(0) = 3 ,y'(0) = -4 The final answer will be...
(d^2 x)/(d t^2) = second order time-derivative term a,b = constant x,θ = variables I'm trying to solve this equation with Equation-Based Modeling (PDE interfaces). But I can't understand how to solve it with COMSOL. Does someone has any idea to solve this problem ?
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Solve for the highest order derivative z" z" = [1+(z')^2]^(3/2) * (2 + (50.99203)*z - (0.1928529/x)) And then follow the examples in the ode45 doc for solving a 2nd order ODE. E.g., the derivative function dzdx = @(x,z) [z(2); ((1+...
Reduction of Order: Given a solution y1 to a second order linear transformation, we can assume that a second solution has the form y=uy1 for some u. Taking derivatives, we have y′=u′y1+uy1′y″=u″y1+2u′y1′+uy1″. Plugging these into the differential equation gives a linear...
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