解:函数fi(x)=1/2 log(_(√2)x-4034•log4i=0,log2x=2017log2i,解得x=ai=i2017,可得数列{an}的前n项和为Sn=1+22017+32017+…+n2017,由于n2017=(n+2-2)2017=(n+2)2017+C_(2017)^1(n+2)2016(-2)+…+C_(2017)^(2016)(n+2)(-2)2016-22017,上式中等号右边的最后的数不...
3【题目】S_n 是等差数列{an}的前n项和, S_(2018)S_(2016)S_(2017)S_(2018) ,则 S_n0 时n的最大值是()A.2017B.2018C.4033D.4034 4【题目】Sn是等差数列 (a_n) 的前n项和,S_(2018)S_(2016) S_(2017)S_(2018) ,则 S_n0 时,n的最大值是()A.2017B.2018C.4033D.4034 ...