windowSum) windowSum -= arr[start] start += 1 return maxSum 计算异位词的...
defmin_window(S,T):n=len(S)m=len(T)start=-1# 记录最小窗口子序列的起始位置minLen=float('inf')# 记录最小窗口子序列的长度i=0j=0whilei<n:ifS[i]==T[j]:j+=1# 在T中找到一个字符,向后移动T的指针ifj==m:# 如果T的指针已经到达末尾,即找到一个包含T的子序列end=i# 记录当前窗口的结...
最简单的sliding window问题:给定一个整数数组,计算长度为 k 的连续子数组的最大总和。 intmaxSum(vector<int>& arr,intk){intmax_sum =0;for(inti =0; i < k; ++i) max_sum+=arr[i];intwindow_sum =max_sum;for(inti = k; i < arr.size(); ++i){ window_sum+= arr[i] - arr[i -k...
1classMinSizeSubArraySum {2publicstaticintfindMinSubArray(intS,int[] arr) {3intwindowSum = 0, minLength =Integer.MAX_VALUE;4intStart = 0;5for(intEnd = 0; End < arr.length; End++) {6windowSum += arr[End];//add the next element7//shrink the window as small as possible until the ...
then the window move one step forward again. [ [1, 5, 3], [3, |2, 1|], [4, |1, 9|], ] 1. 2. 3. 4. 5. ,get the sum13; SO finally, get the maximum from all the sum which is13. 题解: 用sum matrix来表示以[i,j]为右下角点时整个左上方的matrix的和. sum[i][j]...
3. Fixed-Size Sliding Window Let’s look at an example to better understand this idea. 3.1. The Problem Suppose the problem gives us an array of length and a number .The problem asks us to find the maximum sum of consecutive elements inside the array. ...
class Solution { public int maximumUniqueSubarray(int[] nums) { Set<Integer> set = new HashSet<>(); int maxSum = 0; int sum = 0; int left = 0; int right = 0; while (right < nums.length) { sum += nums[right]; while (set.contains(nums[right])) { set.remove(nums[left])...
Easy: Statically Sized Sliding Window: Given an array of integers, find maximum/minimum sum subarray of the required size. Medium: Dynamically Sized Sliding Window: Given an array of positive integers, find the subarrays that add up to a given number. Variation (Medium): Same question but ...
Sliding Window Maximum 2019-12-21 20:19 −Description Given an array of n integer with duplicate number, and a moving window(size k), move the window at each iteration from the start of the... YuriFLAG 0 282 Sliding Window Matrix Maximum ...
4.Find maximum length sequence of continuous ones (Using Sliding Window) Given a binary array, find the index of 0 to be replaced with 1 to get a maximum length sequence of continuous ones. 5.Find the maximum sequence of continuous 1’s formed by replacing at-mostkzeroes by ones ...