size_t interactionMatrix[num_independent_variables][num_independent_variables];
比如以下代码编译有警告: printf("responsed %u:%s\n", strlen(response), response); gh_http.c:288:12: warning: format ‘%u’ expects argument of type ‘unsigned int’, but argument 2 has type ‘size_t {aka long unsigned int}’ [-Wformat=] printf("responsed %u:%s\n",strlen(response)...
比如以下代码编译有警告: printf("responsed %u:%s\n", strlen(response), response);gh_http.c:288:12: warning: format ‘%u’ expects argument of type ‘unsigned int’, but argument 2 has type ‘size_t {aka long unsigned int}’ [-Wformat=]printf("responsed %u:%s\n",strlen(response),re...
$ tests/utf8_test --log_level=test_suite Running 14 test cases... Entering test module "UTF8Test" .../utf8_test.cc(28): Entering test case "ASCII" .../utf8_test.cc(28): Leaving test case "ASCII"; testing time: 462us .../utf8_test.cc(33): Entering test case "Accents" ....
从.rtf文件导入数据时使用int()时出错 将代码从C#转换为Java位操作,将Int64转换为long 从'BYTE* {aka unsigned char*}‘转换为'DWORD {aka long unsigned int}’会丢失精度[-fpermissive] 从timedelta64转换为float时获取NaN 如何在不丢失任何数据的情况下安全地从double类型转换为int类型 ...
This warning appears when compiling with clang on macOS 14: post-process/pp_lexer.c:1098:41: warning: comparison of integers of different signs: 'yy_size_t' (aka 'unsigned long') and 'int' [-Wsign-compare] if ((yyg->yy_n_chars + number_t...
size_t 和int的区别是 size_t是一些C/C++标准在stddef.h中定义的。这个类型足以用来表示对象的大小。size_t的真实类型与操作系统有关，在32位架构中被普遍定义为：typedef unsigned int size_t;而在63位架构中被定义为：typedef unsigned long size_t;size_t在32位架构上是4字节，在64位架构上是...
error: cannot convert 'int*' to 'const size_t* {aka const long long unsigned int*}' for argument '2' to 'mxArray* mxCreateNumericArray_730(size_t, const size_t*, mxClassID, mxComplexity)' plhs[iout] = mxCreateNumericArray(par->ndim,dims,mxL...
问题是你给一个需要int*的函数提供了一个size_t*。你需要做以下之一：
正在产生错误，因为系统上的sz是无符号64位值（long unsigned int），而off_1是有符号64位值（long ...