// printf("printIntPointerArray() finished...\n\n"); } void printCharArray(char * arrayName, char * arr, int length) { // 如果在函数内用sizeof来获得函数外传入的数组长度,会发现数组退化成了指针,获得的只是指针的长度 //printf("\nprintCharArray() loading...\n"); // 打印字符数组元素...
sizeof(int));printf("Size of double: %zu bytes\n",sizeof(double));printf("Size of char: %zu bytes\n",sizeof(char));printf("Size of array: %zu bytes\n",sizeof(arr))
C语言中的sizeof操作符 在C语言中,sizeof是一个编译时操作符,用于获取数据类型或变量在内存中占用的字节数。它可以用于基本数据类型(如int、char等)、结构体、联合体以及指针等。使用sizeof可以帮助程序员了解数据在内存中的布局和大小,从而进行更有效的内存管理。 基本用法 获取基本数据类型的大小: #include <stdi...
printf("Size of double: %zu bytes\n", sizeof(double)); printf("Size of char: %zu bytes\n", sizeof(char)); printf("Size of a: %zu bytes\n", sizeof(a)); printf("Size of b: %zu bytes\n", sizeof(b)); printf("Size of c: %zu bytes\n", sizeof(c)); return 0; } 输出...
#include <stdio.h> struct MyStruct { char a; int b; double c; }; int main() { struct MyStruct s; printf("Size of struct MyStruct: %zu bytes\n", sizeof(s)); return 0; } 求指针的字节数: #include <stdio.h> int main() { int *ptr; printf("Size of pointer: %zu bytes\n...
cout<<"The size of a char is:"<<sizeof(char)//1<<"\nThe length of"<< szHello <<"is:"<<sizeof(szHello)//6,字符串大小 = 本身字符 + '\0'<<"\nThe size of the pointer is"<< getPtrSize(szHello) << endl;//4 ,当64位机时,指针位8字节cout<<"The size of a a array is...
{intmyarray[size];printf("size of myarray = %ld\n",sizeof(myarray));}intmain(intargc,char...
Write a program in C to merge two arrays of the same size sorted in descending order.This task requires writing a C program to merge two arrays of the same size and sort the resulting array in descending order. The program will take inputs for both arrays, merge them, and then sort ...
How do i check how many letters a char array has? If you do not want the additional '\0' you should consider another variable that maintains the size of the contained data. In c++ you have container that will do the work for you though. ...
p_char[0]is an element of the array. A pointer. Size of pointer is not size of string. p_char[0]has alternate syntax: p_char[0] == *p_char == *(p_char + 0) The*(pchar + 2)is thus same aspchar[2]p_char[2]is another element in the array, and so isp_char[1] ...