1、首先打开VS，新建一个 使用sizeof求出数组的大小 project。2、接着在左侧文件树添加一个 sizeof.c 源文件。3、其里面有stdio.h和stdlib.h头文件，也可自己输入。4、然后输入main函数主体及返回值。5、定义一个数组，使用sizeof计算出数组的大小。6、最后编译运行程序，便能输出数组的大小。
计算sizeof(S1)时,min(2, sizeof(i))的值为2,所以i的偏移量为2,加上sizeof(i)等于6,能够被2整除,所以整个S1的大小为6。同样,对于sizeof(S3),s的偏移量为2,c2的偏移量为8,加上sizeof(c2)等于9,不能被2整除,添加一个填充字节,所以 sizeof(S3)等于10。现在,朋友们可以轻松的出一口气了,还有一点要...
charconst*static_string ="Hello";//sizeof(static_string)是sizeof一个指针,所以在32bit system是4charstack_string[] ="Hello";//sizeof(stack_string)是sizeof一个数组,所以是6*sizeof(char)char*string = newchar[6];strncpy(string,"Hello",6");//sizeof(string)是sizeof一个指针,所以还是4。//...
typedef short WORD; typedef long DWORD; cout<<(sizeof(short) == sizeof(WORD))<<endl; // 相等,输出1 cout<<(sizeof(long) == sizeof(DWORD))<<endl; // 相等,输出1 结论:自定义类型的sizeof取值等同于它的类型原形。 (3)函数类型 考虑下面的问题: int f1(){return 0;}; double f2(){re...
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32位C++中的基本数据类型,也就char,short int(short),int,long int(long),float,double, long double 大小分别是:1,2,4,4,4,8, 10。 考虑下面的代码: cout<<sizeof(unsigned int) == sizeof(int)<<endl; // 相等,输出 1 unsigned影响的只是最高位bit的意义,数据长度不会被改变的。