General solution for |sinx|=cosx is 2npi+pi/4,\ n in I (b) 2npi+-pi/4, n in 1 npi+pi/4,\ n in 1 (d) none of these
Solve (general solution is not needed): tan x + tany =2, 2cosx cosy=1 03:01 Find the least positive values of x and y: sin(x-y)=1/2, cos(x+y)=1/2. 02:01 Find the least positive values of x and y so that 2(sinx + siny)-2cos(... 10:38Exams...
f(x)=∫(sinx)^9dx=-∫(sinx)^8d(cosx)=-∫(1-cos^2x)^4dcosx 令cosx＝t f(t)=-∫(1-t^2)^4dt=x-4x^3/3+6x^5/5-4x^7/7+x^9/9+C 带入t=cosx就可以了
dxdy=sinxcosxcos2y 視頻 Degrees to radians (video) | Trigonometry | Khan Academy khanacademy.org Solving Trigonometric Equations Using Identities, Multiple Angles, By Factoring, General Solution YouTube Solving Trigonometric Equations By Factoring & By Using D...
y=arccos(sin(x)) 解x x=−arcsin(cos(y))+2πn1+π,n1∈Z x=arcsin(cos(y))+2πn2,n2∈Z,y≥0andy≤π 解y y=arccos(sin(x)) 圖表
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Mathematics - General MathematicsA005In this paper, we investigate the one-variable equation, sinx+cosx+tanx+cotx+secx+cscx=n, where n is an integer. We prove that if n lies between(inclusively) -1 and 6; then the above equation has no real number solutions. While if n is greater than...
现以y=(sinx-2)/(3+2cosx)为例,探讨形如y=(c+dsinx)/(a+bcosx)函数的最值求法.解法1:(利用三角函数的有界性)视函数为关于x的方程,变形得 王爱枝,李连庆 - 《中学生数理化:高中版》 被引量: 0发表: 2002年 求函数y=(asinx+bcosx+c)/(a'sinx+b'cosx+c')值域的一种简便方法 求函数y=(asinx...
比如你不能用sinx^2+cosx^2=1去证明勾股定理。等你真要去证明一个很基础的定理的时候,你会发现很多工具都不能用了,因为那些工具都是基于这个定理推出的。就像别人要炼钢造大炮,钢不够,你说那还不简单,把现有的大炮融了炼钢啊?这是没意义的。另一方面,当时工具也没那么多,你怎么去证?不能脱离时代背景。就像...
This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerQuestion: Find derivative of (sinx)/(1-cosx) Find derivative of (sinx)/(1-cosx) Here’s the best way to solve it. Solution 100% (1 rating) Share ...