LeetCode Problem 136:Single Number 描述:Given an array of integers, every element appearstwiceexcept for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题目要求O(n)时间复杂度,O(1)空间复杂度。 思路1...
1classSolution:2#@param {integer[]} nums3#@return {integer}4defsingleNumber(self, nums):5bitNum = [0] * 326foriinrange(32):7foreinnums:8bitNum[i] += (e >> i) & 19ans =010fori, valinenumerate(bitNum):11ifi == 31andval % 3 !=0:12ans = -((1 << i) -ans)13else:1...
Can you solve this real interview question? Single Number II - Given an integer array nums where every element appears three times except for one, which appears exactly once. Find the single element and return it. You must implement a solution with a li
Problem Highlights 🔗 Leetcode Link: Single Number 💡 Problem Difficulty: Easy ⏰ Time to complete: 15 mins 🛠️ Topics: Array, Hashset, XOR 🗒️ Similar Questions: Single Number II, Single Number III, Missing Number 1: U-nderstand Understand what the interviewer is asking for...
Can you solve this real interview question? Single Number III - Given an integer array nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. You can return the a
Credits: Special thanks to @.fighter for adding this problem and creating all test cases. class Solution { public: //两个不同的数出现一次,其余两次,异或 vector<int> singleNumber(vector<int>& nums) { int n,ans1,ans2; ...
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Special thanks to@jianchao.li.fighterfor adding this problem and creating all test cases. Solution Two-pass XOR, time O(n), space O(1) 先取XOR,然后找到XOR中二进制为1的一位,然后根据它将nums分成两个group,然后分别取XOR即可。 classSolution{publicint[]singleNumber(int[]nums){intxor=0;for(...