【leetcode】数组中找出只出现一次的数字(Single Number),题目是这样说的:Givenanarrayofintegers,everyelementappears twice exceptforone.Findthatsingleone.Note:Youralgorithmshouldhavealinearruntimecomplexity.Couldyouimplementitwit
LeetCode——Single Number(找出数组中只出现一次的数) 问题: Given an array of integers, every element appearstwiceexcept for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 分析: 数组中的数除了一个只出...
1classSolution(object):2defsingleNumber(self, nums):3"""4:type nums: List[int]5:rtype: int6"""7ifnotnums:8return09res =nums[0]10foriinrange(1, len(nums)): # 从头开始遍历11res = res ^nums[i] # 异或12returnres
classSolution{public:intsingleNumber(vector<int>&nums){intans=nums[0];intn=nums.size();for(inti=1;i<n;i++)ans=ans^nums[i];returnans;}}; 第二题题目:Given anon-emptyarray of integers, every element appearsthreetimes except for one, which appears exactly once. Find that single one.给...
问题https://leetcode-cn.com/problems/single-number/ 练习使用JavaScript解答 /** * @param {number[]} nums * @return {number} */ var singleNumber = function(nums) { var a = 0, i; for(i=0;i<nums.length;++i) { ...
Can you solve this real interview question? Single Number - Given a non-empty array of integers nums, every element appears twice except for one. Find that single one. You must implement a solution with a linear runtime complexity and use only constant
260 Single Number III 只出现一次的数字 III Description: Given an integer array nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. You can return the answer in any order. ...
*/publicclassLeetCode_136{publicintsingleNumber(int[]nums){intresult=0;intlen=nums.length;for(inti=0;i<len;++i)result^=nums[i];returnresult;}publicstaticvoidmain(String[]args){LeetCode_136leetCode=newLeetCode_136();System.out.println(leetCode.singleNumber(newint[]{2,2,1}));System.out...
leetcode 算法解析(一):260. Single Number III 260.Single Number II 原题链接 本题其实算是比较简单,在 leetcode 上也只是 medium 级别,ac 率也很高,最好先自己尝试,本文只是单纯的记录一下自己整体的思路; 在阅读本文章之前,最好先解锁本题的简单模式136.Single Number,这对理解本题有较大的帮助;...
详细的题目描述见上一篇博客《leetcode-137-Single Number II-第一种解法》,这里简单说一下。 有一个数组,所有元素都出现了三次,除了一个元素只出现了一次。输出这个只出现一次的元素。 要求时间复杂度O(n),空间复杂度O(1)。 要完成的函数: int singleNumber(vector<int>& s) ...