百度试题 结果1 题目【题目】若$$ \tan \theta = 3 $$,求$$ \sin 2 \theta - \cos 2 \theta $$的值 相关知识点: 试题来源: 解析 【解析】 【答案】$$ \frac { 7 } { 5 } $$ 反馈 收藏
Step by step video & image solution for सिद्ध कीजिए की (1+ sin 2theta -cos 2theta ) /( 1+ sin 2theta + cos 2theta) =tan theta by Maths experts to help you in doubts & scoring excellent marks in Class 11 exams.Updated on:21/07/2023Class...
【证明】方法一:左边$$ = \frac { \sin 2 \theta + ( 1 - \cos 2 \theta ) } { \sin 2 \theta + ( 1 + \cos 2 \theta ) } $$ $$ = \frac { 2 \sin \theta \cos \theta + 2 \sin ^ { 2 } \theta } { 2 \sin \theta \cos \theta + 2 \cos ^ { 2 } \the...
Step by step video & image solution for यदि x=cos theta-cos 2theta और y=2 sin theta-sin 2 theta, तो सिद्ध कीजिए (dy)/(dx)="tan"(3theta)/(2) by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. Upd...
Answer to: Derive and prove the double angle formula: sin 2 theta = 2 sin theta cos theta and cos 2 theta = cos^2 theta - sin^2 theta By signing...
$-\cos \theta$【诱导公式】 sin(a+k·2π)=sin,cos(a+k·2T)=cosa, 公式一 tan(a+k·2元)=tana(其中k∈Z) sin(+a)=-sina,cos(T+a)=-cosa 公式二 tan(π+a)=tan sin(-a)=-sin a,cos(-a)=cosa 公式三 tan(-a)=-tan a sin(-a)=sin a,cos(-a)=-cosa 公式四 tan...
sin(2θ)−cos(θ)=0sin(2θ)-cos(θ)=0 使用正弦倍角公式。 2sin(θ)cos(θ)−cos(θ)=02sin(θ)cos(θ)-cos(θ)=0 从2sin(θ)cos(θ)−cos(θ)2sin(θ)cos(θ)-cos(θ)中分解出因数cos(θ)cos(θ)。 点击获取更多步骤... ...
$$ 解 : 原式 = \frac { 2 \sin \theta \cos \theta - ( \cos ^ { 2 } \theta - \sin ^ { 2 } \theta ) } { \sin ^ { 2 } \theta + \cos ^ { 2 } \theta + \cos ^ { 2 } \theta } \\ = \frac { 2 \sin \theta \cos \theta - \cos ^ { 2 } \theta...
theta=2npior 2npi+pi/2, n in IFind the value of theta, which satisfy 3-2 cos theta-4 sintheta-cos 2theta + sin 2theta=0.
જો x=2sin theta -sin 2 theta અને y= 2cos theta -cos2 theta , theta in [0,2 pi ] તો [(d^2y)/dx^2](theta =pi)=