(vi)1+tan2θ1+secθ=secθ Show that [[cos theta,-sin theta],[sin theta,cos theta]]=[[1,-tan(theta)/(2)],[tan(theta)/(2),1]][[1,tan(theta)/(2)],[-tan(theta)/(2),1]]^(-1) सिद्ध कीजिए की :cosθ1+sinθ=tan(π4−θ2) य...
Answer to: Write the following in terms of sin theta and cos theta, then simplify if possible. \frac{\tan\theta}{\cot\theta} By signing up, you'll...
Answer to: Write the following in terms of sin theta and cos theta, then simplify if possible. \sin\theta\tan\theta + \sec\theta By signing up,...
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若\sin \theta \cdot \tan \theta >0,则\theta 的终边在( ). A. 第一、二象限 B. 第二、三象限 C. 第三、四象限 D.
tan(θ)=sin(θ)tan(θ)=sin(θ) 将tan(θ)=sin(θ)tan(θ)=sin(θ) 中的每一项除以 tan(θ)tan(θ) 并化简。 点击获取更多步骤... 1=cos(θ)1=cos(θ)将方程重写为 cos(θ)=1cos(θ)=1。 cos(θ)=1cos(θ)=1取方程两边的逆余弦从而提取余弦内的 θθ。 θ=arccos(1)θ=arccos(1...
What is 2sin(2θ−4π)−cos(2θ) in terms of trigonometric functions of a unit θ ? https://socratic.org/questions/what-is-2sin-theta-2-pi-4-cos-theta-2-in-terms-of-trigonometric-functions-of-a-u Please look below. Explanation: 2sin(2θ−4π)−cos(2θ) =2(sin(2...
\theta角的象限: (1) \sin \theta >0且 \tan \theta >0; (2) \sin \theta \cdot \cos \theta >0. 相关知识点: 试题来源: 解析 由可知终边可能落在第一、二象限,轴非负半轴; 由可知终边可能落在第一、三象限; 综上所述,结论:为第一象限角 由可知: 或 故为第一、三象限角; 综上所述...
已知tan\theta =2,\theta 为第三象限角,则sin\theta =( )。A. \frac{2\root \of {5} }{5} B. -\frac{2\root \of {5} }{5} C. \frac{\root \of {5} }{5} D. -\frac{\root \of {5} }{5} 相关知识点: 试题来源: 解析 B...
tan(θ)=2tan(θ)=2,sin(θ)<0sin(θ)<0 The sine function is negative in the third and fourth quadrants. The tangent function is positive in the first and third quadrants. The set of solutions forθθare limited to the third quadrant since that is the only quadrant found in both sets...