正弦(sin)余弦(cos)正切(tan)余切(cot)正割(sec)余割(csc) 小数位 工具简介: 本工具支持在线计算常见的三角函数值(正弦、余弦、正切、余切、正割、余割),以及对应的反三角函数值(反正弦、反余弦、反正切等)。 操作简单、结果精确,适用于学习、编程、工程计算等场景。 📌注意:本工具使用的是“弧度(r
We can calculate {eq}\sin \ \cos \ and \ \tan {/eq} without a calculator by using the concept of Pythagoras theorem as we know, $$\displaystyle...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our experts can answer your...
代数输入 三角输入 微积分输入 矩阵输入 0.01343863071187315−1 =74.41234315014631 求值 26877261423746320000000000000000≈74.41234315 因式分解 7⋅1567⋅24502927727217⋅516=74268772614237463110826546427738=74.41234315014633
百度试题 结果1 题目Using a Calculator to Find the Value of a Ratio sin。sin OCOSo COS Otan tan _ ° 相关知识点: 试题来源: 解析 sin120° sin35° 0.866 0.574 cos17° cos100° 0.956 -0.174 tan 45° +an 174° 1 -0.105 反馈 收藏 ...
Answer to: Use identities to find the following values. Do not use a calculator. tan theta=3 and cos theta less than 0. (a) sin2theta (b) cos2theta...
Use a calculator to estimate the value of the following. Round to the nearest ten-thousandth. sin 83.6 degree Use a calculator to approximate the value of the expression, if possible. Round your result to two decimal places. (Write your answer in radia...
This is a simple calculator website made with the help of HTML, CSS and JavaScript. It has functionality of basic calculator such as Arithmetic as +, -, *, / and Trigonometric such as sin, cos, tan, etc. - Dhruvil-Joshi/Calculator
Value of tan 45° = 1 Substituting the Values, = 2(1/2) + 3(1/2)- 3(1) = 1+ 3/2 – 3 = - 1/2 3( Cos 30°)2 + 2( Sin 30°)2 Ans: Value of Cos 30° = 32 Value of Sin °30 = 12 Substituting the values, =3(32)2+2(12)2 =3(3/4) + 2(1/4) = 9/4...
Key Details of SIN COS TAN Calculator The simple and fast way to calculate six basic trigonometric function values in degrees and radians. Last updated on August 5, 2018 There have been 6 updates Virus scan status: Clean (it’s extremely likely that this software program is clean)Developer’...
对此函数求积分 (-sin(x))/(3*tan(x)-2*cos(x)) 自变量为 x: -4*(log(abs(sin(x)^2/(cos(x)+1)^2+sin(x)/(cos(x)+1)+1))/10+log(abs(sin(x)^2/(cos(x)+1)^2-(4*sin(x))/(cos(x)+1)+1))/40-log(sin(x)^2/(cos(x)+1)^2+1)/8)+C −4 ⎜ln(...