是的，因为弧度的单位是1，积完分就是个实数，而角度制中单位是度，积分时就不能用一般的数了。微分也是一样。
College Mathematics JournalRichman, F. (1993). A circular argument. The College Mathematics Journal, 24(2), 160 - 162. [4] Schaumberger, N. (1984). The derivatives of sin x and cos x. The College Mathematics Journal, 15(2), 143 - 145....
1. Derivatives of the Sine, Cosine and Tangent Functions by M. Bourne It can be shown fromfirst principlesthat: d(sinx)dx=cosx\displaystyle\frac{{{d}{\left( \sin{{x}}\right)}}}{{{\left.{d}{x}\right.}}}= \cos{{x}}dxd(sinx)=cosx...
Some useful derivatives are {eq}\displaystyle \frac{d}{dx}\sin x =\cos x {/eq} {eq}\displaystyle \frac{d}{dx}\cos x = -\sin x {/eq} Answer and Explanation:1 Given {eq}\displaystyle y=2\sin x \cos x {/eq} Differentiating with respect to {eq}\displaystyle x {/eq} we get...
Rat and Their Bioactivities The structures of the condensed tannins isolated from leaf, fruit, and stem bark of Delonix regia (Bojer ex Hook.) Raf. have been investigated with C-13 nu... WM Chai,Y Shi,石艳,... - AMER CHEMICAL SOC 被引量: 66发表: 2012年 Tanshinone IIA harmonizes the...
Find :∫sinx+cosx√sin2xdx View Solution ∫sinx+cosx√1+sin2xdx View Solution Evaluate:∫sinx−cosx√sin2xdx View Solution ∫sinx+cosx√1+sin2xdx. Evaluate:∫sinx+cosx√1−sin2xdx View Solution Evaluate:∫sinx+cosx√1−sin2xdx ...
Here, in the first formula and in the last formula either the upper signs or the lower signs are used throughout. The products of trigonometric functions can be converted into a sum or difference by means of the formulas The derivatives of the trigonometric functions can be expressed in terms...
NDA PREVIOUS YEARS-DERIVATIVES-MCQs What is the derivative of x^(3) with respect to x^(2)? 00:54 If f(x)=2x^(2)+3x-5, then what is f'(0)+3f'(-1) equal to? 01:08 What is the derivative of sin(sinx)? 00:41 What is the derivative of |x-1| at x = 2? 01:23 What...
Find the derivative: y=cosθ1+sin2θDerivatives:As the given function is trigonometric we must know the derivatives of the trigonometric functions. As the function is the quotient of the two functions we will apply the quotient rule of derivatives: ...
The derivative of (sin x)^sin x is cos x * (sin x)^sin x * (ln(sin x) + cos x * ln(sin x)). This can also be written as (sin x)^sin x * (cos x * ln(sin x) + ln(cos x)) How do you find the derivative of (sin x)^sin x?