所以2\sin\alpha (2-\sin\alpha )=1-2\sin^2\alpha , 所以\sin\alpha ={1\over 4}, 因为\alpha \in (0,{\pi\over 2}), 所以\cos\alpha ={\sqrt{15}\over 4},\tan \alpha ={\sqrt{15}\over 15}。 故本题正确答案为A。 反馈 收藏 ...
Concerning the Definition by a System of Functional Properties of the Function$f (z) = {sin \\pi z} \\over \\pi$ 来自 JSTOR 喜欢 0 阅读量: 23 作者: E. Hastings Moore 摘要: stable/info/1967504 DOI: 10.2307/1967504 被引量: 2 ...
F4 Thailand: Boys Over Flowers (2021–2022) (TV Series) - Jane (3 episodes, 2021) The Tulip Mania (一月 29, 2022) Season 1, Episode 6 - Jane (as Patchara Tubthong) See more 3 Irresistable (2021) (TV Series) - Gina (14 episodes, 2021) Episode #1.22 (十二月 14, 2021)...
(1)求函数f(x)再1区间[0,\pi]上单调递增区间; (2)将函数f(x)的图象向左平移\varphi -{\pi}\over{24} 个单位长度得到函数g(x)的图象,若\varphi \in (0,\pi)且tan\varphi ={3}\over{4} ,求函数g(x)在区间[0,{\pi}\over{2} ]上的取值范围。相关...
F4 Thailand: Boys Over Flowers(2021–2022) (TV Series)-Jane(3 episodes, 2021) The Tulip Mania(一月 29, 2022)Season 1, Episode 6-Jane (as Patchara Tubthong) See more 3 Irresistable(2021) (TV Series)-Gina(14 episodes, 2021) Episode #1.22(十二月 14, 2021)Season 1, Episode 22-Gina ...
曲线\(y = \sin x\) 在点\(({\pi \over 2},1)\)处的曲率为 ()A.\({1 \over 2}\)B.\(1\)C.\(2\)D.\(3\)的答案是什么.用刷刷题APP,拍照搜索答疑.刷刷题(shuashuati.com)是专业的大学职业搜题找答案,刷题练习的工具.一键将文档转化为在线题库手机刷题,以提高学习效率,是...
若(cos α=- dfrac {2}{3}),则( dfrac {cos (4π-α)sin (-α)}{sin ( dfrac {π}{2}+alpha )tan (pi -alpha )})的值为 ___ . 免费查看参考答案及解析 题目: 将函数(y=sin (x+ dfrac {π}{6}))的图象向左平移(π)个单位,则平移后的函数图象(() ()) A、关于直线(x= dfrac...
First, we must know that the secant function is the inverse function... Learn more about this topic: Trigonometric Functions | Cotangent, Secant & Cosecant from Chapter 16/ Lesson 2 19K Learn to define what trigonometric functions are. Discover the cotangent, secant and cosecant formulas. Lear...
(1)因为f(x)=3\sin({x\over2}+{\pi\over6})+3,\omega ={1\over 2} , 所以函数f(x)的最小正周期为{2\pi\over|\omega |}=4\pi, 则函数f(x)周期为T=4\pi,振幅为3,初相为{\pi\over6}, 由{x\over2}+{\pi\over6}={\pi\over2}+k\pi, 得x={2\pi\over3}+2k\pi...
Plot the sine function over the domain−π≤x≤π. x = -pi:0.01:pi; plot(x,sin(x)), gridon Sine of Vector of Complex Angles Calculate the sine of the complex angles in vectorx. x = [-i pi+i*pi/2 -1+i*4]; y = sin(x) ...