In this question a simplification of a square root will be made where the property of the root will be used, specifically that of the division, to find the adequate result of the solution. Answer and Explanation: To solve this question a simplification will be m...
diagonal; // returns 1D array of the matrix's diagonal if square matrix, empty array otherwise m.det; // returns the matrix's determining : det(M) m.toString(); // returns the 2D matrix as a string m.at(x, y); // returns the element at position (x,y) in the matrix m.set(...
To find those roots, you can rewrite the function as a quadratic equation, then move the constant over to the right and take the square root of both sides:In the domain of real numbers, the square root is only defined for nonnegative input values. Therefore, calling this function in ...