Simplify (2x - 1)^3. Simplify: \dfrac{3}{y-1}+\dfrac{5}{4y} Simplify: (y^4) (y^3). Simplify: (3x - 3)/(7x - 3) times (x + 1)/(x^2 - 1). Simplify. \frac{\frac{2x^2-8x}{x^2-16{\frac{8x^2}{(x+4)^2 ...
3. Expand and simplify: 5x(3x−2)−4x(2x+3)5x(3x−2)−4x(2x+3)5x(3x−2)−4x(2x+3) 23x2−22x23x2−22x23x2−22x 7x2−57x2−57x2−5 7x2−22x7x2−22x7x2−22x 7x2−2x7x2−2x7x2−2x 4. Expand and simplify: 5(6x−2y)−2(8x...
Simplify (x^2)/x Simplifying Algebraic Expressions: In mathematics, when given an algebraic expression, we simplify it by rewriting it in its simplest form. To do this, we use various tools such as combining like terms, cancelling like factors, factoring, etc. The tools we use depend on th...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
Find y'. Do not simplify. y=frac{2}{sqrt x}-5sin x+7x^4 Simplify \sqrt{a^5b^2c} How do you simplify (-1/2)(7z + 4) + (1/5)(5z - 16)? How do you simplify (4x^2)^3 (3x^6 )^4? How do you simplify 7/8 + 5/6?
Step by step video & image solution for Simplify :2x(x-3)+2 and find its value for x = 1. by Maths experts to help you in doubts & scoring excellent marks in Class 8 exams. Updated on:21/07/2023 Class 8MATHSALGEBRAIC EXPRESSIONS AND IDENTITIES ...
Simplify: (x^{1/2} \ast z^{-4/5})^{4} Simplify x^(1/2) + 2x^(3/2). Simplify x^(1/2) * x^(1/3) Write the expression with rational exponents. - 8 \sqrt{x} If f(x)= \sqrt{x}, find a way to rewrite \frac{f(x+h)-f(x)}{h} that does not have h as factor...
百度试题 结果1 题目Simplify: (7x-1)(2x+5) () A. 14x^2+33x-5 B. 14x^2-33x-5 C. 14x^2+37x+5 D. 14x^2-14x-5 相关知识点: 试题来源: 解析 A 反馈 收藏
indices:1.(x^5*x^6)/(x^3) 2.(x^7*x^4)/(x^2) 3.(3x^2*x^4)/(x-5) 4.(5x^3*4x^2)/(2x^3) 5.(8x^5*3x)/(12x^2) 6.(3x^2*2x-1)/(7x) 7.(2x^3*5x)/(15x-6) 8.(x^8*3x^(-6))/(x^5) (2x^2y^3*6x^2y)/(4xy^2) 89.10.3x2y3x6x-1y39x3y2...
(x^2-x-12)/(x^2-16)*(2x^2+7x-4)/(x^2-4x-21) Factor wherever possible is always the first step. = ((x-4)(x+3))/((x-4)(x+4))*((x+4)(2x-1))/((x+3)(x-7)) Apply the basic rule of fractions. (Three pairs of factors divide out.) = (2x-1)/(x-7) ...