sqrt(2)/2 + cmath.sqrt(2)/2*1j >>> z0**4 (-1.0000000000000004-0j) >>> (z0**4).real -1.0000000000000004 You’ll notice that the resulting value isn’t exactly -1 due to the rounding error in floating-point arithmetic. To account for that, you can call cmath.isclose() whenever...
If 0 argument is given, float between 0 and 1 pow(x, p); // power of x, default power beeing 2 sqrt(x); // sqrt of x min(a, b, c, ...); // minimum between all given values max(a, b, c, ...); // maximum between all given values abs(x); // absolute of x ...
return sqrt((s.width * s.width) + (s.height * s.height)); } //INCHES static Size inches(BuildContext c) { Size pxSize = size(c); return Size(pxSize.width / _ppi, pxSize.height/ _ppi); }static double widthInches(BuildContext c) => inches(c).width;static double...