你可以假设,结果将是在32位有符号整数的范围。 翻译结果2复制译文编辑译文朗读译文返回顶部 你可能假设结果将在 32 位被签署的系列整数中。 翻译结果3复制译文编辑译文朗读译文返回顶部 你可能会假定结果将范围内的 32 位带符号整数。 翻译结果4复制译文编辑译文朗读译文返回顶部 您可以假设结果将是在32位签名整数范...
aYou may assume the result will be in the range of 32-bit signed integer 您可以假设结果将是在32位签名整数范围内[translate]
Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range. 重点来了: For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows. 所以我们应该考虑溢出,我们用一个long的数据类型来容纳int类型的运输,...
a signed 32bit integer cOutputOutput just one pair of signed 32bit integers a and b.Sample Input17Sample Output14 3HintThis is a SPJ.For Sample input,You may also output "12 5" instead.The signed 32bit integers range in [-2147483648,2147483647].///是求两个数加起来等于c吗?那让其中一...
md5-x86_64.s:77: Error: 0xf57c0faf out range of signed 32bit displacement md5-x86_64.s:95: Error: 0xa8304613 out range of signed 32bit displacementMany more errors like this. 解决方法: #vim openssl-0.9.8e/crypto/md5/asm/md5-x86_64.pl ...
1).计算机最小的存储单位是“位” 也就是bit或binary digits,用来存放一个二进制数,即 0或1。 8个二进制位为一个字节Byte。 2).对于 16-bit(16位)的计算机,int是以两个字节来储存的,而32-bit的计算机,则是以4个字节,即32个bit来储存的。
# Blender integer layers are 32bit signed and will throw an # exception if we are assigning an unsigned value that # can't fit in that range. Reinterpret as signed if necessary: if val < 0x80000000: layer.data[v.index].value = val else: layer.data[v.index].value = struct.unpack('...
Int32 Implements GlAdd GlAliasedLineWidthRange GlAliasedPointSizeRange GlAlpha GlAlphaBits GlAlphaTest GlAlways GlAmbient GlAmbientAndDiffuse GlAnd GlAndInverted GlAndReverse GlBack GlBlend GlBlueBits GlByte GlCcw GlClampToEdge GlColorArray GlColorBufferBit GlColorLogicOp GlColorMaterial GlCompressedTextu...
TheVERIFY_ARE_EQUALmacrocompares its two parameters and reports a test failure if they are not equal. The customer found that the above code compiled okay for x86-64, but produced the indicated error when compiled for x86-32. What’s going on?
So we can represent the negative values -128..-1 and the non-negative values 0..127 with a single eight bit byte. With a 16-bit word we can represent values in the range -32,768..+32,767. With a 32-bit double word we can represent values in the n-1 n-1 range -2,147,483...