百度试题 结果1 题目Ex. 4)Show that the following points are collinear by determinant method.A(2, 5), B(5, 7), C(8, 9) 相关知识点: 试题来源: 解析 2+∫_(x_1)x_2 六、 反馈 收藏
Show that the following points are collinear: (i) A(2, -2), B(-3, 8) and C(-1, 4) (ii) A(-5, 1), B(5, 5) and C(10, 7) (iii) A(5, 1), B(1, -1) and C(11, 4) (iv) A(8, 1), B(3, -4) and C(2, -5) ...
To show that the points A(2, 3, 4), B(-1, 2, -3), and C(-4, 1, -10) are collinear, we can use the concept of the section formula. We will find the ratio in which point C divides the line segment AB.Step 1: Assume the ratio Let
If {eq}\, {\bf c} = \|{\bf a}\|{\bf b} + \|{\bf b}\|{\bf a}, \, {/eq} where {eq}\, {\bf a}, {\bf b},\, {/eq} and {eq}\, {\bf c}\, {/eq} are all nonzero vectors, show that ...
a. Show that the points A(-1,3), B(3,11), and C(5,15) are collinear (lie on the same line) by showing that |AB|+|BC|=|AC| b. Use slopes to show that A, B and C are collinear. Find the points in which the line x = 1 + 2t...
The biological basis of the increased risk for psychiatric disorders seen in 15q11.2 copy number deletion is unknown. Previous work has shown disturbances in white matter tracts in human carriers of the deletion. Here, in a novel rat model, we recapitula
“Panama”). The combination of eliminated and retained metabolic pathways of the bacterium indicates a potential for a mutualistic as well as for a parasitic relationship, whose outcome could depend on the environmental context. In particular we show that the endosymbiont is dependent on the host ...
A k-arc K of PG(2, q) is a set of k points no three of which are collinear. If q is even then k q + 2, if q is odd then k q + 1. A k-arc is called complete if it is not contained in a ( k + 1)-arc. B. Segre considered the following pro... JA Thas - 《...
A set S of 2n+1 points in the plane is said to be in general position if no three points of S are collinear and no four are concyclic. A circle is called halving with respect to S if it has three points of S on its circumference, n-1 points in its interior, and n-1 in its...
If {eq}\, {\bf r}(t) = {\bf a} \cos \omega t + {\bf b}\sin \omega t,\, {/eq} where {eq}\, {\bf a}\, {/eq} and {eq}\, {\bf b}\, {/eq} are constant vectors, show that {eq}\, ...