开发者ID:rajuyohannan,项目名称:codeigniter-admin,代码行数:7,代码来源:Group.php 示例4: _render_query ▲点赞 2▼ protectedfunction_render_query(){if(empty($this->_config)) {show_error("No están definidas las configuraciones para el elemento select_fk: {$this->_name}"); }// array(//...
codeigniter calling show_error from a library I can't manage to call show_error from inside a library file I get Warning: include(application/errors/error_php.php) [function.include]: failed to open stream: No such file or directory in E:\project\SOURCE\system\core\Exceptions.php on line...
I am using Whoops error handling framework with my CodeIgniter framework to display errors. Whoops catches php syntax errors and displays them nicely, as expected. The problem is that Whoops cannot display PHP Errors with severity as Notice, because they are caught by CodeIgniter core and displayed...
Did you view your server error files? Did you hit F-12 key in your web browser to see what the error is? What did you Try? What did you Get? What did you Expect? Joined CodeIgniter Community 2009. ( Skype: insitfx )Reply MENU...
用mysql实现Codeigniter中的“create view”和"Other query“合并问题 查看Snowflake中CREATE View语句的DDL历史记录 使用view获取MySQL表中多行的结果 如何避免create view必须是批处理中唯一的语句错误? UsersController#create中的NoMethodError --你是说超级吗?
codeigniter saving posts twice I have a Codeingiter application that stores posts into a database using jquery! but the problem is that it stores same data twice! I reviewed the code but I can't seem to figure it out! please help m... ...
以前一直show()肯定是display:block,但是今天写jq的时候发现不是这样的,有时候却出现是display:inline。 简单看了下jquery此处的实现源码 if( show ) {//Reset the inline display of this element to learn if it is//being hidden by cascaded rules or notif( !values[ index ] && elem.style.display =...
i have written like this in c# below is the pinvoke declaration in c# ...My database connection doesn't connect with postgreSQL the code is written for the connection but the function pg_connect() doesn't work with the framework and database i.e. codeigniter and postgreSQL. to connect ...
die("Connection failed: ". $conn->connect_error); } $sql ="SELECT id, firstname, lastname FROM MyGuests"; $result = $conn->query($sql); if($result->num_rows>0){ while($row = $result->fetch_assoc()){ echo"id: ". $row["id"]." - Name: ". $row["firstname"]." ". ...
Fatal error: require_once(): Failed opening required '/www/wwwroot/fengshanping.com/system/core/CodeIgniter.php' (include_path='.:/www/server/php/56/lib/php') in /www/wwwroot/fengshanping.com/index.php on line 204