0)and he wants to reach position(n - 1, m - 1), Knight can only be from left to right. Find the shortest path to the destination position, return the length of the route. Return-1if knight can not reached.
class Solution { public: int shortestPathBinaryMatrix(vector<vector<int>>& grid) { int n = grid.size(); // If the starting point or ending point is 1, then you will not be able to start or end, so return -1 if( grid[0][0] || grid[n-1][n-1] ) return -1; // Consider...
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