Attempt all questions. Each of 4 marks.(i) R={(1,1)(2,2)(3,3)(4,4)(2,3)(3,2)} is the relation on set A={1,2,3,4} Check reflexive, symmetric and transitive relation. View Solution Let A={2,3,4,5} R={(2, 2),and let R(3,3),(4,4),(5,5),(2,3),(3,2)...
Represents a set of questions being asked. The question set is used to link all the individual requests where different recipients were asked the same set of questions on the same subject.
: to cause to assume a specified condition, relation, or occupation The bird was treated and then set free. They accidentally set the house on fire. b : to cause the start of set a fire 7 a : to appoint or assign to an office or duty b : post, station 8 : to cause ...
The set x is said to be an ordinal if x is transitive and the∈-relation well-orders x, i.e., if (a) x is transitive, (b) for all u∈x we have u∉u, (c) for all u, v, w in x, if u∈v∈w then u∈w, and (d) every non-empty subset z of x has a member u...
Membership is the basic relation. There is natural relationship between sets and logic. for example, if A is a set, the P(x) = " x∈A " is a formula that expresses whether x is a membership of A or not. So the questions come out naturally :what is the universe of the constructed...
Prove that there is a subset X of R2 satisfying the relation card(l∩X)=k(l)for each straight line l in R2. This beautiful result is due to Sierpiński and it generalizes some theorems of Mazurkiewicz and Bagemihl. Prove, in the theory ZF, that there exists a set Y ⊂ R2 ...
Let {eq}A ~\text{and}~ B {/eq} are two sets then, a relation that is defined from {eq}A~ \text{to}~B {/eq} is called a function from {eq}A~ \text{to}~B {/eq}, if (1). for each element(a) of {eq}A {/eq} there exist an element(b) of {eq}B {/eq}...
RELATIONS AND FUNCTIONSBook:ICSEChapter:RELATIONS AND FUNCTIONSExercise:EXERCISE 2 (c) Explore 26 Videos RELATION AND FUNCTIONSBook:ICSEChapter:RELATION AND FUNCTIONSExercise:MULTIPLE CHOICE QUESTIONS (Choose the correct answer from the given four options in questions) Explore 32 Videos SAMPLE QUESTION PAP...
This method will re-index all your lft, rgt and depth column values, inspecting your tree only from the parent <-> children relation standpoint. Which means that you only need a correctly filled parent_id column and Baum will try its best to recompute the rest. This can prove quite usefu...
This leads to the idea of the support function of K. Definition. If K is a closed convex set then the support function of K, hK(f), is defined by: hKf:=supfx:x∈K. The support function is a sublinear function. If K is bounded, then hK is finite for all x and we may replace...