concise Chemistry class 10 ICSE Solutionsfor chapter 4 that is given here will help students get a clear insight into the important concepts and topics. These solutions include detailed explanations and accurate answers to all the questions given at the end of the chapter. Stu...
construction of circumscribed and inscribed circles of a triangle and constructing a circumscribed and inscribed circle on a regular hexagon. Understanding these constructions are very essential as at least one question is expected from this chapter in the ICSE. So, students having any difficulties...
Chemistry 8(2/E) by John West Chemistry for Middle Class 8 by RP Rana Noms ICSE Chemistry for Class 8 by Amarnath Mishra Biology: Concise ICSE Biology for Class 8, Selina Publishers Noms Biology 8(2/e) by PA Paulose Biology for Middle Class 8 by AP Mishra ...
Exercise 10(E) Solutions Access Selina Solutions Concise Mathematics Class 6 Chapter 10: Sets Exercise 10(A) Exercise 10(A) 1. State whether or not the following elements form a set, if not, give reason: (i) All easy problems in your text book. ...
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Students can access theICSE Class 8 Selina Solutionsfor all questions from Maths, Physics, Chemistry and Biology subjects at one place. We hope this information on “ICSE Class 8 Maths Selina Solutions Chapter 7 Percent and Percentage” is useful for students. Keep learning and stay tuned for ...
Access Selina Solutions Concise Mathematics Class 6 Chapter 1 Number System Exercise 1(a) Page no: 5 1. Which is greater? (i) 537 or 98 (ii) 2428 or 529 (iii) 2, 59, 467 or 10, 35, 729 Solution: (i) 537 or 98 Here 537 is a three digit number and 98 is a two digit numb...
ICSE Class 8 Maths Selina Solutions Chapter 5 Playing with Number – Exercise 5 (B) Question 1. Solution: A=7 as 7+5=12. We want 2 at units place and 1 is carry over. Now 3+2+1=6 B=6 Therefore, A=7 and B=6 Question: 2 ...
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6. A class contains 25 children, of which 6 are girls. What percentage of the class are the boys Solution: Total number of children in the class = 25 Number of girls = 6 Number of boys = 25 – 6 = 19 boys Thus, percentage of boys in the class = 19 / 25 × 100 ...