publicstaticint[]Sort(int[]array){//记录数组长度intlength =array.length;//外层循环for(inti=0;i<length-1;i++){//将最小数下标记录为iintmin_index = i;//内层循序 遍历i后边的数组for(intj=i+1;j<length;j++){if(array[j]<array[min_index]){//如果当前遍历到的数小于当前最小索引的对应...
publicclassselectionSort {publicstaticvoidmain(String[] args){int[] toBeSorted = {1,54,3,8,6,0};//k记录当前已排完序的最后一个元素的位置,//temp用于交换时候的临时变量//为了避免每次都要重新申请内存,所以将两个变量提出来放在函数外面intk, temp;for(inti = 0; i < toBeSorted.length; i++)...
/** * 选择排序 * @author chenpeng * */ public class SelectionSort { //我们的算法类不允许产生任何实例 private SelectionSort() {} public static void sort(int[] arr) { int n = arr.length; for(int i=0;i<n;i++) { //寻找区间里最小值的索引 int minIndex =i; for(int j=i+1;j...
第n轮:重复同样的操作直到所有数字都归位为止,排序完成。 选择排序(Selection Sort)代码实现: public class Demo { public static void main(String[] args) { int[] array= {6,1,7,8,9,3,5,4,2}; int[] newarray=selectionSort(array); for(int arr:newarray) { System.out.print(arr+" "); }...
import java.util.Arrays; /** * Selection Sort Implementation In Java * * @author zparacha * * @param <T> */ public class SelectionSort<T extends Comparable<T>> { int size; T[] data; public SelectionSort(int n) { data = (T[]) new Comparable[n]; } public void insert(T a) ...
1、找出一个最小数交换到最前面 2、在剩下的数中找个最小的交换到剩下数最前面 3、一直重复此步骤,直到所有数排好顺序。 时间复杂度:O(n^2) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. import java.util.Arrays; public class SelectionSort { ...
因为789456123，这算是一个数字，args的长度也就是一 可以改为：String[] s = args.split();int[] a = new int[s.length];for(int m = 0; m < a.length; m++){ a[m] = new Integer(s[m]);}
Java C C++ # Selection sort in PythondefselectionSort(array, size):forstepinrange(size): min_idx = stepforiinrange(step +1, size):# to sort in descending order, change > to < in this line# select the minimum element in each loopifarray[i] < array[min_idx]: min_idx = i# put...
Java Program Implementation Let's implement the selection sort algorithm: public void sort(int arr[]) { int n=arr.length; int min_ind; for(int i=0;i<n;i++) { min_ind = i; for(int j=i+1;j<n;j++) { if(arr[min_ind] > arr[j]) ...
The idea was to first swap all 1's and 2's using 2 pointers and then swap all 0's and 1's to sort them followed by 1's and 2's → Reply » » MohammadParsaElahimanesh 4 months ago, # ^ | 0 I guess you cannot sort it well and you have infinite loop witch led to...