学过For循环都知道,要先对这个循环进行计数,然后循环到我们需要的那一次再取值。那么SQL中怎么计数呢。答案是使用COUNT方法。 COUNT方法 SELECTe1.SalaryFROMEmployee e1WHERE2=(SelectCount(distinct(e2.Salary))fromEmployee e2wheree2.Salary>=e1.Salary)asSecondHighestSalary; 上面两种方法也可以用于,取任意第N位...
https://leetcode.com/problems/second-highest-salary/ 首先MySQL不支持top语法,要用limit代替。 selectSalaryfromEmployeeorderbySalarydesclimit1,1 这样写的话如果不存在,select出来是空,题目需要是null(掀桌。 Input: {"headers": {"Employee":["Id", "Salary"]}, "rows": {"Employee":[[1, 100]]}} ...
For example, given the above Employee table, the second highest salary is200. If there is no second highest salary, then the query should returnnull. 解决方案如下: # Write your MySQL query statement below select max(Salary) from Employee where Salary<(select max(Salary) from Employee ) 1. ...
1. 2. View Code 这个,用一个子查询可以不用isnull判断的 # Write your MySQL query statement below select ((select distinct Salary from Employee order by Salary desc limit 1 offset 1)) as 1. 2. 这个错的 SELECT DISTINCT Salary AS SecondHighestSalary FROM Employee ORDER BY Salary DESC LIMIT ...
Salary GROUP BY a.Id HAVING COUNT(a.Id) = 1) AS SecondHighestSalary; 3.3 Leetcode 答案 SELECT (SELECT DISTINCT Salary FROM Employee ORDER BY Salary DESC LIMIT 1 OFFSET 1) AS SecondHighestSalary; 类似之前我提到的,如果没用子查询,会有一样的问题:当没有薪水第二高的人的时候,返回的不是null...
Can you solve this real interview question? Second Highest Salary - Table: Employee +---+---+ | Column Name | Type | +---+---+ | id | int | | salary | int | +---+---+ id is the primary key (column
Write a SQL query to get the second highest salary from the Employee table. +---+---+ | Id | Salary | +---+---+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +---+---+ For example, given the above Employee table, the query should return200as the second highest salary. If...
Can you solve this real interview question? Second Highest Salary - Table: Employee +---+---+ | Column Name | Type | +---+---+ | id | int | | salary | int | +---+---+ id is the primary key (column
编写一个 SQL 查询,获取Employee表中第二高的薪水(Salary) 。 创建表和数据: droptableEmployee; CreatetableIfNotExistsEmployee (Idint, Salaryint); insertintoEmployee (Id, Salary)values('1','100');insertintoEmployee (Id, Salary)values('2','200');insertintoEmployee (Id, Salary)values('3','30...
Write a SQL query to get the second highest salary from theEmployeetable. +---+---+ | Id | Salary | +---+---+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +---+---+ For example, given the above Employee table, the second highest salary is200. If there is no second high...