Example 3.4. (see [2]) Let X = Y = R2, G = {0}, x0 = (3.9, .9), x1 = (4, 1), and define operator F on X by F (x, y) = (y2 − 4, x2 − 2 y − 21). Our method (1.5) generates the solution x⋆ = (5, 2) of (1.1)
Secant method Convergence analysis Recurrence relations A priori error bounds Integral equations 1. Introduction In this paper, we study the solution of nonlinear integral equations of the Hammerstein type [4], [6], [7]:(1)x(s)=h(s)+∫01R(s,t)p(t,x(t))dt,where x,h∈C[0,1],R(...
8. The biocontainment vessel of claim 1, wherein the enhancement composition is located with respect to the structural composition such that the augmentation agent benefits biological cells contained in the biocontainment vessel. 9. A method of containing biological cells, the method comprising: placing...