百度试题 结果1 题目12.已知角α的终边经过点 P(8m,6m)(m≠q0) ,求 log2| seca-tana的值. 相关知识点: 试题来源: 解析 12.当 m0, log2 seca-tana -1;当 m0时, log2| seca-tana|=1. 反馈 收藏
分析:此题可以化为正弦,余弦来证,但较 繁琐.如将 sec^2α-tan^2α=1 分解为(seca+ tanα)(sinα-tanα)=1 ,构造等比数列:seca+ tana,1,seca-tana来证明,就容易多了. 证明:由 (secα+tanα)(secα-tanα)=1 可令 secα+tanα=q,secα-tanα=1/q ,则左边 = q seca+tana-1 q-1__ ...
The value of (secA + tanA-1) (sec A -tanA+1) -2tanA is equal to View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, ...
1 + tan2 30 ∘ tanA1+secA−tanA1−secA=2cosecA View Solution 1+secAsecA=sin2A1−cosA. View Solution Prove that secA(1−sinA)(secA+tanA)=1. View Solution secA(1−sinA)(secA+tanA)=? View Solution (secA+tanA−1)(secA−tanA+1)−2tanA= ...
答案解析 查看更多优质解析 解答一 举报 seca-tana=-1/3,而sec^2a-tan^2a=1(seca-tana)(seca+tana)=1所以seca+tana=-3所以seca=(-1/3-3)/2=-5/3tana=-4/3所以sina=tana/seca=-4/3/(-5/3)=4/5 解析看不懂?免费查看同类题视频解析查看解答 ...
结果一 题目 急,书不在旁边,三角函数tanA,cotA,secA.cscA的微分公式是? 答案 1、d(tanA)=(secA)^2dA2、d(cotA)=-(cscA)^2dA3、d(secA)=secAtanAdA4、d(cscA)=-cscAcotAdA相关推荐 1急,书不在旁边,三角函数tanA,cotA,secA.cscA的微分公式是?
解析 左边-(1+x/x+y/x)/(1+x/x-y/x)=(x+y+y)/(x+y-y)- \frac([(x+r)+y][x+r)+y]([(x+r)-y][(x+r)+y]=\frac((x+r+y)^2)((x+r)^2-y^2) =(2x^2+2xy+2xy+2y^2)/(2x^2+2xy)=((r+y)(x+r))/(x(x+r)) r+y 1+ 1+sina =右边 cosa ...
2secA-tanA=(2-sinA)/cosA P(0,2)和Q(-cosA,sinA)cos^2A+sin^2A=1 y=k(x-2),x^2+y^2=1 1=(-2k)/根号（1+k^2）k=根号3/3或k=－根号3/3 2secA-tanA的最大值＝根号3/3 2secA-tanA的最小值＝－根号3/3
secA-tanA=1 问secA和tanA是多少? 最简单的方法:三角恒等式:secA*secA-tanA*tanA=1也就是:(secA+tanA)*(secA-tanA)=1于是,secA+tanA=1再有:secA-tanA=1易得:secA=1且tanA=0注:三角恒等式secA*secA-tanA*tanA=1由定义即可证明.
Answer Step by step video & image solution for sqrt((secA-tanA)/(secA+tanA))=(1-sinA)/(cosA)=cot((pi)/(4)+(A)/(2)). by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams.Updated on:21/07/2023 ...