Prove thatsec2θ−sin2θtan2θ=cosec2θ−cos2θ. View Solution sec2θ+cosec2θ= ………. View Solution √sec2θ−tan2θ+cot2θ= ……….. View Solution (1−sec2θ)(1−cosec2θ)= ………. View Solution Doubtnut is No.1 ...
Ifsec−1(2)+cosec−1(y)=π2, then find y . 01:56 View Solution ∫ π/2 3Secx+5cosecxSecx+cosecx dx 02:50 View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths
integral tanx^2dx = integral secx^2 - 1dx [since tan^2x+1=sec^2x] = 1/2 tanx – X +C [integralsec^2x=tanx] Thanks and Regards
(a). (sec ^2θ )((cosec) θ )= sec θ ⋅ tan θsince (sec^2 θ)((cosec) θ) = ((1(cos θ))^2)( 1(sin θ))= (1(cos^2 θ))(1(sin θ))= (sin θ)(cos^2 θ)= (sin θ)(cos θ)⋅ 1(cos θ)= sec θ ⋅ tan θSo (sec^2 θ)((cosec)θ)=sec ...
sec 函数的定义域为所有不等于 π/2+kπ(k 为整数)的实数,因为在这些点上 sin(x)=0,sec(x)无定 义。 接下来,我们来看 cosec 公式。cosec 函数是正弦函数的倒数,即 cosec(x)=1/cos(x)。根据三角函数的定义,cos(x)=邻边/斜边,因此 cosec(x)=斜边/邻边。在直角三角形中,邻边是斜边与角度所对应...
【题目】cosec^2θ+sec^2θ=cosec^2θsec^2θ 相关知识点: 试题来源: 解析 【解析】L.H.S.cosec^2θ+sec^2θ =1/(sin^2θ)+1/(cos^2θ) =(cos^2θ+sin^2θ)/(sin^2θcos^2θ) =1/(sin^2θcos^2θ) =cosec^2θsec^2θL.H.S. = R.H.S.Prove. ...
For R. dominica adults, mortalities were recorded as 90% and 92.4% for SilocoSec and local DE, respectively. Additionally, mortality of T. confusum at 2000 mg/kg wheat was 100% for both DE samples. Results showed that local DE and SilocoSec are equally effective against t...
Integrate the following functions with respect to x: sec ^2x, (cosec)^2x, cos ^2 12x, tan ^2x [Hint: use sec ^2x=1+tan ^2x], cot ^2x 相关知识点: 试题来源: 解析 tan x, -cot x, 12x+ 12sin x, \ tan x-x, -cot x-x 反馈 收藏 ...
y'=-cosec^2((√x)/2) * 1/(4√x)+sec^2(2/(√x)) * (-1)/(x√x) 该题求导需要使用链式法则和三角函数的导数公式。分别对两个复合函数求导,得到: y'=-cosec^2((√x)/2) * 1/(4√x)+sec^2(2/(√x)) * (-1)/(x√x)。 最终结果为: y'=-cosec^2((√x)/2) ...
【题目】若(cosec^2(2π-θ))/(sec^2(π+θ))=3 θ) (3π)/2θ2π 302π,求sec2(π+0)sinθ的值. 相关知识点: 试题来源: 解析 【解析】(1-sin^2θ)/(sin^2θ)-3sin^2θ-1/4,θ∈((3π)/2,2π) θ∈((3π)/2,2π)sinθ=-1/2 ...