classSolution {publicintsearch(int[] nums,inttarget) {returnsearch(nums, 0, nums.length - 1, target); }privateintsearch(int[] nums,intlow,inthigh,inttarget) {if(low >high)return-1;intmid = (low + high) / 2;if(nums[mid] ==target)returnmid;if(nums[mid] <nums[high]) { //后...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). You are given a target value to search. If found in the array return its index, otherwise return-1. You may assume no duplic...
publicintsearch(int[]nums,inttarget){intstart=0;intend=nums.length-1;//找出最小值的数组下标/* while (start < end) {int mid = (start + end) / 2;if (nums[mid] > nums[end]) {start = mid + 1 ;} else {end = mid;}}int bias = start;*///找出最大值的数组下标while(start<end...
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; 6. if(A[mid] == target) 7. return mid; 8....
LeetCode-Search in Rotated Sorted Array Description: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). You are given a target value to search. If found in the array return...
Search in Rotated Sorted Array 描述 Suppose a sorted array is rotated at some pivot unknown to you beforehand. 2.1 数组 5 (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return ...
sort that is theoretically optimal in terms of the total number of writes to the original array, unlike any other in-place sorting algorithm. It is based on the idea that the permutation to be sorted can be factored into cycles, which can individually be rotated to give a sorted result....
题目 33. Search in Rotated Sorted Array 题解 题目意思就是在一个上升序列中截断成AB 两个子序列 然后BA拼接成一个新的序列, 而题目要求 我们查找在这个序列中是否存在target,如果看到这里就会发现 这个很简单啊,查找一个序列中是否有某个数字 直接遍历就好了 方法木佬佬,但是 最重要的是题目末尾有一句 ...
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array)33. 搜索旋转排序数组整数数组 nums 按升序排列,数组中的值 互不相同。在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1...
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