Find the node in the BST that the node's value equalsvaland return the subtree rooted with that node. If such a node does not exist, returnnull. Example 1: Input:root = [4,2,7,1,3], val = 2Output:[2,1,3] Example 2:
TreeNode* searchBST(TreeNode* root,intval) {while(root && root->val !=val) { root= (root->val > val) ? root->left : root->right; }returnroot; } }; 类似题目: Closest Binary Search Tree Value Insert into a Binary Search Tree 参考资料: https://leetcode.com/problems/search-in-a-...
因为题目给的二叉树是BST,其中序遍历的节点值是从小到大排列且有序的,因此,直接使用中序遍历的顺序,按照左子树-->根-->右子树的顺序遍历即可。 // 借助中序遍历,左根右的顺序publicTreeNode searchBST(TreeNode root, intval) {// 先判空if(root ==null) {returnnull; }// 如果val大于当前节点值,就往...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. 注意,可能存在多种有效的插入方式,...
image.png For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition. 大意: 给出一个二叉查找树(BST),在其中找到给出的两个节点的最低的共同祖先(LCA...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia:“The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (wher...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (wh...
题目链接:https://leetcode.com/problems/lowest-common-ancestor-of-a-binary-search-tree/ 题目: Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to thedefinition of LCA on Wikipedia: “The lowest common ancestor is defined betw...
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class BSTIterator: def __init__(self, root: Optional[TreeNode]): # 初始化一个空结点栈(所有结点的左子结点...
今天介绍的是LeetCode算法题中Easy级别的第163题(顺位题号是700)。给定一个二叉搜索树(BST)的和正整数val。 你需要在BST中找到节点的值等于给定val的节点。返回以该节点为根的子树。如果此节点不存在,则应返回null。例如: 鉴于树: 4 / \ 2 7 / \ 1 3 ...