*@return*/publicbooleansearchMatrix(int[][] matrix,inttarget) {if(matrix ==null)returnfalse;introw =matrix.length;if(row == 0)returnfalse;if(matrix[0] ==null)returnfalse;intcolumn = matrix[0].length;if(column == 0)returnfalse;if(target < matrix[0][0] && target > matrix[row - 1...
bool searchMatrix(vector<vector<int> > &matrix, int target) { if(matrix.size() == 0) return false; int m = matrix.size(); int n = matrix[0].size(); if(target < matrix[0][0] || target > matrix[m-1][n-1]) //目标元素不在矩阵中 return false; int low = 0, high = m ...
如果target是和matrix[i][n-1]比较来确定target所在行的话,则上面代码注释地方恰好要使用matrix[above]了: classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.empty() || matrix[0].empty())returnfalse;if(target < matrix.front().front() || target > matrix....
来自专栏 · LeetCode 每日一题 题意 给定一个 m * n 的整数矩阵 matrix ,每一行从左到右升序,每一行的第一个数字比上一行的最后一个数字大,判断 target 是否在这个矩阵中? 数据限制 m == matrix.length n == matrix[i].length 1 <= m, n <= 100 -(10 ^ 4) <= matrix[i][j], target <...
[LeetCode]Search a 2D Matrix Question Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ...
https://leetcode.com/problems/search-a-2d-matrix-ii/description/ 题解一 九章算法提供的比较巧妙的解题思路,从matrix 左下角开始向右上角遍历, 初始: introwIndex=matrix.length-1;intcolIndex=0; 逻辑主体: ifcurrentItem == target, return true; ...
Solution1 Code: classSolution1{publicbooleansearchMatrix(int[][]matrix,inttarget){if(matrix==null||matrix.length<1||matrix[0].length<1){returnfalse;}introw=0;intcol=matrix[0].length-1;while(col>=0&&row<=matrix.length-1){if(target==matrix[row][col]){returntrue;}elseif(target<matrix...
# Write an efficient algorithm that searches for a value in an m x n matrix. # This matrix has the following properties: # # Integers in each row are sorted from left to right. # The first integer of each row is greater than the last integer of the previous row. # For example, #...
Can you solve this real interview question? Search a 2D Matrix - You are given an m x n integer matrix matrix with the following two properties: * Each row is sorted in non-decreasing order. * The first integer of each row is greater than the last int
大家可以看完讲义结合 LeetCode Book 二分查找练习一下 问题定义 给定一个由数字组成的有序数组 nums,并给你一个数字 target。问 nums 中是否存在 target。如果存在, 则返回其在 nums 中的索引。如果不存在,则返回 - 1。 这是二分查找中最简单的一种形式。当然二分查找也有很多的变形,这也是二分查找容易出错...