来自专栏 · LeetCode 每日一题 题意 给定一个 m * n 的整数矩阵 matrix ,每一行从左到右升序,每一行的第一个数字比上一行的最后一个数字大,判断 target 是否在这个矩阵中? 数据限制 m == matrix.length n == matrix[i].length 1 <= m, n <= 100 -(10 ^ 4) <= matrix[i][j], target <...
方法一: 1classSolution {2public:3boolsearchMatrix(vector<vector<int> > &matrix,inttarget)4{5introw =matrix.size();6intcol = matrix[0].size();7intsubRow =0;8if(row ==0|| col ==0)returnfalse;910//寻找行11if(matrix[row -1][0] <= target)//最后一行,特殊处理12subRow = row -...
如果target是和matrix[i][n-1]比较来确定target所在行的话,则上面代码注释地方恰好要使用matrix[above]了: classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.empty() || matrix[0].empty())returnfalse;if(target < matrix.front().front() || target > matrix....
bool searchMatrix(vector<vector<int> > &matrix, int target) { if(matrix.size() == 0) return false; int m = matrix.size(); int n = matrix[0].size(); if(target < matrix[0][0] || target > matrix[m-1][n-1]) //目标元素不在矩阵中 return false; int low = 0, high = m ...
https://leetcode.com/problems/search-a-2d-matrix/ 题目: m x n Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous row. For example, Consider the following matrix: ...
LeetCode 240. Search a 2D Matrix II 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending ...
[10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ] Giventarget=5, returntrue. Giventarget=20, returnfalse. 左上角最小右下角最大, 先让raw =0; col = n-1; 如果target在这范围内col--,如果不在row++ 代码很简单, leetcode 大神多!
"""m=len(matrix)ifm==0:returnFalsen=len(matrix[0])ifn==0:returnFalsei=0whilei<m:iftarget>=matrix[i][0]:i+=1else:breakifi==0:returnFalseelse:ifmatrix[i-1][n-1]<target:returnFalseelse:flag=Falseforjinrange(n):ifmatrix[i-1][j]==target:flag=Truebreakreturnflag ...
Can you solve this real interview question? Search a 2D Matrix - You are given an m x n integer matrix matrix with the following two properties: * Each row is sorted in non-decreasing order. * The first integer of each row is greater than the last int
Integers in each c...LeetCode 240. Search a 2D Matrix II Search a 2D Matrix II 这个solution复杂度为O(row + column) 主要思想是从右上角开始搜索,行列元素值递增,所以当前元素小于target时,target会出现在当前行下方,当当前元素大于target时,target谁出现在当前列左侧。......