Hello, I used scanf() in a while loop, which ensures that user input is valid (must be an integer no greater than 21 or less than 3). If user enters a number out of the range, or enters non-number, he/she will be asked to retry. /* start */ int n; wh
int a[maxsize];int c[maxsize];printf("enter number of elements(disks)\n");printf("enter the elements in ascending order\n");{ } 这有时工作良好,但大多数情况下 浏览2提问于2015-03-28得票数 1 5回答 scanf忽略,无限循环 、、 int flag = 0;while (flag==0) printf("\nEnter Product pr...
Ok I have a while loop here which contains a switch statement (I have only fleshed out case 1) and functions normally , except for when in case 1 I hit CTRL-D (for EOF, could be CTRL-Z for you). This sends it into an infinite loop and ignores the scanf at the top...
输入非匹配字符串时Scanf不在while循环中工作 我使用一个名为checkType的函数来检查用户是否输入了一个有效的integer类型的输入。例如,如果用户输入15,它将打印有效,而15c将打印无效。但是,如果用户只像cccccc一样输入字符串,就会导致无限循环,程序崩溃。我在下面添加了一些屏幕截图来显示输出。 int checkType(int input...
c scanf infinite-loop 希望你能帮助我,我必须使用scanf来读取和验证输入。。。我尝试过以下代码: int num = 0; while( scanf("%d",&num) != 1 || num < 3 || num > 9){ printf("Enter new num: "); } 当我输入数字时,它工作得很好,但当我输入任何其他字符时,它进入无限循环,而不是要求新...
// scanf() is used in a loop #include<stdio.h> intmain() { charc; printf("Press q to quit "); do{ printf("Enter a character "); scanf("%c",&c); printf("%c ",c); }while(c!='q'); return0; } 输出 Pressq to quit ...
C scanf in循环自动继续，无需输入我的问题很容易解决。我是在思考我的投入后找到的。问题是，在输入...
*/ scanf("%[0-9]", string); printf("string = %s\n", string); 键盘输入： 12345...
C语言中while语句里使用scanf的技巧 今天友人和我讨论了一段代码,是HDU的OJ上一道题目的解,代码如下 #include<stdio.h>{inta,b;while(~scanf("%d%d",&a,&b)) { printf("%d\n",a+b); }return0; } 起初,我以为代码中while语句里的按位取反运算符写错了,应该是逻辑非运算符。
C - Infinite loop with scanf in while loop, Add a comment. 0. The cause of the infinite loop is that if you input a letter, the "\n" that follows it is taken as the input of scanf () function within the next loop. So you can simply add "getchar ()" to fix it. Note the ...