scala 调用 java cannot resolve overloaded method 当在Scala中调用Java代码时出现"cannotresolveoverloadedmethod"错误时，通常是因为在Java类中存在多个同名方法但参数类型不同，而Scala在解析方法时无法确定要调用哪个方法。 要解决这个问题，你可以尝试以下几种方法： 1.显式地指定参数类型：在调用Java方法时，明确...
Instead, use copy constructor. Having mutable case classes can be error prone, e.g. hash maps might place the object in the wrong bucket using the old hash code. // This is OK case class Person(name: String, age: Int) // This is NOT OK case class Person(name: String, var age: ...
无法在scala中为log4j2创建自定义Appender在Java中，你可以用super(arguments)调用构造函数中的超类构造函数...
However, do NOT use them in constructors, especially when a and b need to be marked transient. The Scala compiler generates an extra Tuple2 field that will not be transient for the above example.class MyClass { // This will NOT work because the compiler generates a non-transient Tuple2 ...
If the class should be created using a constructor, document it using the @constructor syntax:/** A person who uses our application. * * @constructor create a new person with a name and age. * @param name the person's name * @param age the person's age in years */ class Person(...